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- Xref: sparky sci.math:17477 sci.physics:21833
- Path: sparky!uunet!pipex!bnr.co.uk!uknet!mcsun!sunic!seunet!front.se!samuel
- From: samuel@front.se
- Newsgroups: sci.math,sci.physics
- Subject: Re: Three-sided coin
- Message-ID: <1992Dec28.221925.130@front.se>
- Date: 28 Dec 92 21:19:25 GMT
- References: <1992Nov10.032643.10467@galois.mit.edu> <1dp0m9INNkq6@agate.berkeley.edu> <jim.721702281@st-michael>
- Organization: Samuel Gustaf Siren
- Lines: 30
-
- In article <jim.721702281@st-michael>, jim@cs.UAlberta.CA (Jim Easton) writes:
-
- > Given that it is possible to bounce from one state to another it
- > is more probable to bounce out of a high energy state to a lower
- > energy state than it is the reverse. I claim that the lowest energy
- > state is the most probable and therefore conclude that the three states
- > should be equal in energy.
- >
- > That implies that the thickness is equal to the diameter.
-
- I agree with you to a certain extent. However, if the thickness is equal to the
- diameter, then wouldn't (assuming that your energy-state-theory is correct) the
- coin behave similar to a cube, where the sides of the coin correspond to two
- sides of the cube and the 'edge' of the coin corresponds to FOUR sides of the
- cube. This would imply that the probability for head id 1/6, tail 1/6 and
- 'edge' 4/6 = 2/3. I'm not sure that I'm entirely correct on this one, but I'm
- almost sure that the probability for 'edge' would be significantly higher than
- the one for head or tail, given that the thickness is equal to the diameter.
- /SS
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