home *** CD-ROM | disk | FTP | other *** search
- Path: sparky!uunet!dtix!darwin.sura.net!gatech!swrinde!sdd.hp.com!ux1.cso.uiuc.edu!news.cso.uiuc.edu!dbradley
- From: dbradley@symcom.math.uiuc.edu (David Bradley)
- Newsgroups: sci.math
- Subject: G=Ab Gp. H<G => G/H embedds in G, don't use Hom(G,Q/Z)
- Message-ID: <Bzn3GF.Gt@news.cso.uiuc.edu>
- Date: 22 Dec 92 02:41:03 GMT
- Sender: usenet@news.cso.uiuc.edu (Net Noise owner)
- Organization: Math Dept., University of Illinois at Urbana/Champaign
- Lines: 10
-
- This has probably been discussed before, but could someone please
- nudge me in the right direction on this one? It's not homework.
-
- Let G be an abelian group and H a subgroup. Then G has a subgroup
- isomorphic to G/H. I managed to prove this using the isomorphism
- G ~ Hom(G,Q/Z), but surely there is a more direct proof, perhaps
- based on the structure theorem for finite abelian groups. This is
- embarassing.
-
- -D.M.Bradley
-