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- Path: sparky!uunet!think.com!hsdndev!husc-news.harvard.edu!husc8!mcirvin
- From: mcirvin@husc8.harvard.edu (Mcirvin)
- Newsgroups: sci.physics
- Subject: Re: Inelastic versus Elastic
- Message-ID: <mcirvin.722467020@husc8>
- Date: 22 Nov 92 21:17:00 GMT
- References: <1992Nov22.101430.455@news.wesleyan.edu>
- Lines: 31
- Nntp-Posting-Host: husc8.harvard.edu
-
- BBLAIS@eagle.wesleyan.edu (BRIAN S. BLAIS) writes:
-
- >A friend of mine wrote me:
- >--
- >Suppose that you have a bullet running into a block. It does so in a perfectly
- >inelastic manner. That is, the bullet stays in the block after the collision
- >imparting its momentum into the combination of itself and the block. However,
- >some of the energy of the motion is lost in the form of heat, so kinetic
- >energy is not conserved.
-
- >Why? I am looking for an intuitive explanation of the conservation of moment
- >that allows one to see clearly and distinctly that, even though some of the
- >quantity of motion is converted into heat, the quantity of motion as expressed
- >by _mv_ remains the same.
- >--
-
- Here's a possibly satisfactory way of looking at it. When the bullet
- slams into the block it sets various small components of the block jiggling
- about in thermal motion. These little objects (atoms, say) therefore
- possess both momenta and kinetic energies. Kinetic energy is a scalar
- quantity, just a number, so the kinetic energies add up to some amount
- which came from the bullet. But momentum is a vector quantity, so the
- momenta associated with the atoms' thermal motions (relative to the
- block+bullet's center of mass) cancel out, since they're going in all
- different directions. So the thermal motions can't take up momentum from
- the bulk motion of the block and bullet.
-
- I hope that was intuitively satisfying...
- a
- --
- Matt McIrvin
-