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- Newsgroups: sci.physics
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- From: dacosta@prl.philips.nl (Paulo da Costa 42147)
- Subject: Re: TIME HAS INERTIA. Att: Da COSTA FUND. THM. OF ALGEBRA
- Message-ID: <1992Nov22.140904.16605@prl.philips.nl>
- Keywords: Explanation re: Abian's proof of FUNDAMENTAL THM. OF ALGEBRA
- Sender: news@prl.philips.nl (USENET News System)
- Organization: none
- References: <1992Nov19.074930.15845@CSD-NewsHost.Stanford.EDU> <1992Nov20.100104.17600@prl.philips.nl> <By19zL.F1C@news.iastate.edu>
- Date: Sun, 22 Nov 1992 14:09:04 GMT
- Lines: 29
-
- In article <By19zL.F1C@news.iastate.edu> abian@iastate.edu (Alexander Abian) writes:
- >Mr Da Costa, you wrote:
- >
- >> so the expansion is not valid in the vicinity of z=0, where he
- >>proceeded to use it (the expansion converges for z *outside* a radius
- >>of convergence that includes all zeros of his polynomial .......
- >> It's bullshit. Satisfied?
- >
- > My answer to you is:
- >
- >Yes, you are absolutely correct; the expansion converges for z OUTSIDE
- >A RADIUS OF CONVERGENCE THAT INCLUDES ALL ZEROS OF MY POLYNOMIAL.
- >
- > BUT, but, you forgot that we ASSUMED THAT THE POLYNOMIAL HAS NO ZEROS
- >and therefore the expansion is valid EVERYWHERE [...]
-
- No, it isn't. "Long division" gives you two possible Laurent
- expansions, one in _ascending_ and one in _descending_ powers of z. If
- your polynomial has no root, one of these will be valid everywhere, the
- other won't be valid at all. By pointing out the obvious fact that the
- latter does _not_ converge in the vicinity of z=0, the only thing you
- do is to prove that the former (the Taylor series) is the one which
- converges everywhere, and you shoot yourself in the foot.
-
- Once again, what a load of crap.
-
- --
- -- Paulo da Costa /\/\ Minha terra tem palmeiras /\/\
- -- dacosta@prl.philips.nl \/\/ Onde canta o sabia'... \/\/
-