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- Path: sparky!uunet!charon.amdahl.com!pacbell.com!ames!haven.umd.edu!decuac!pa.dec.com!nntpd2.cxo.dec.com!nntpd.lkg.dec.com!star.enet.dec.com!abbasi
- From: abbasi@star.enet.dec.com (My name is Nasser Abbasi)
- Subject: Question on the energy of EM field , why the missing term in Feynman book?
- Message-ID: <1992Nov17.090201.21642@nntpd.lkg.dec.com>
- Sender: usenet@nntpd.lkg.dec.com (USENET News System)
- Organization: Digital Equipment Corporation
- Date: Tue, 17 Nov 1992 09:01:34 GMT
- Lines: 39
-
-
- Hi,
-
- Iam looking at "the Feynman lectures on physics" VOL 2, page 27-5
- equation 27.13
-
- this relates to an EM field energy.
-
- he said that the rate of doing work by the EM field on a unit matter , which
- is E.J is equal to
- - DIV S - du/dt
-
- where S is the Poynting vector (power leaving region), and du/dt is the
- rate of change of the energy density of the field inside the region.
-
- this is all fine, but my question is on E.J part (ie. the left hand side
- of the question).
-
- why did he not also add the H.M term to E.J ? H.M is the rate of work done by
- the magnetic field component on the "magnetic current". (H is the magnetic
- field intensity, and M is the magnetic current density, J is the current
- density, E is the electric field intensity).
-
- he only considered the power done by the electromotive part of the field (E),
- and did not look at the power done by magnomotive (sp?) part?
-
- I looked at "Time-Harmonics Electromagnetic fields" by Roger F. Harrington,
- page 11, equation 1-38, and there, Harrington does show the power due to
- the magnetic part as well as the electric part as the sources for the power
- of the EM field.
-
- can some also please give a short word or a pointer on how to best look at
- the power supplied by magnetic field (i.e. H.M) I find this one harder, it is
- easy to see the power supplied the Electric filed (E.J) but not the (H.M).
-
- than you,
- /nasser
-
-
-