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- Path: sparky!uunet!decwrl!waikato.ac.nz!comp.vuw.ac.nz!kauri.vuw.ac.nz!harper
- Newsgroups: sci.astro
- Subject: Re: Distance of horizon
- Message-ID: <By54vv.A2C@comp.vuw.ac.nz>
- From: harper@kauri.vuw.ac.nz (John Harper)
- Date: Sun, 22 Nov 1992 23:21:30 GMT
- Sender: news@comp.vuw.ac.nz (News Admin)
- References: <lglhj3INNb0c@appserv.Eng.Sun.COM> <csLkuB9w165w@west.darkside.com>
- Organization: Victoria University of Wellington
- Nntp-Posting-Host: kauri.vuw.ac.nz
- Lines: 17
-
- In article <csLkuB9w165w@west.darkside.com> max@west.darkside.com (Erik Max Francis) writes:
- >fiddler@concertina.Eng.Sun.COM (steve hix) writes:
- >
- >> Anyone have handy a function for figuring the distance of the
- >> horizon from a viewer based on the viewer's height from the
- >> surface?
- >
- >I calculated it a while ago to be
- >
- > s = r arctan [(h^2 + 2 h r)/r^2]^(1/2).
- Refraction makes a significant difference. Mount Ruapehu is 2797m = 9175ft
- high and about 150 miles or 230 km away. It can occasionally be seen from
- various local hills. It makes a difference of around 300m or 1000ft (from
- memory not recent calculation) to calculate how much of the mountain can
- be seen with and without allowing for refraction.
-
- John Harper Mathematics Dept. Victoria University Wellington New Zealand
-