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- Path: sparky!uunet!cis.ohio-state.edu!magnus.acs.ohio-state.edu!csn!scicom!wats
- From: wats@scicom.AlphaCDC.COM (Bruce Watson)
- Newsgroups: sci.astro
- Subject: Re: Distance of horizon
- Message-ID: <31074@scicom.AlphaCDC.COM>
- Date: 21 Nov 92 01:10:38 GMT
- References: <1992Nov19.021430.13833@sfu.ca| <75439@hydra.gatech.EDU> <1992Nov20.131437.8385@cs.com>
- Organization: Alpha Science Computer Network, Denver, Co.
- Lines: 32
-
- In article <1992Nov20.131437.8385@cs.com| jack@cs.com (Jack Hudler) writes:
- |In article <75439@hydra.gatech.EDU> collins@emperor.gatech.edu (Tom Collins) writes:
- |>In article <1992Nov19.021430.13833@sfu.ca> palmer@sfu.ca (Leigh Palmer) writes:
- |>>In article <lglhj3INNb0c@appserv.Eng.Sun.COM> fiddler@concertina.Eng.Sun.COM
- |>>(steve hix) writes:
- |>>>Anyone have handy a function for figuring the distance of the
- |>>>horizon from a viewer based on the viewer's height from the
- |>>>surface?
- |>> -1
- |>>Try d = R arccos ( 1 + h/R )
- |>>
- |>> d = horizon distance
- |>> h = height above MSL (assuming horizon is at sea level)
- |>> R = radius of Earth
- |>
- |> 2 2 2
- |>since R + d = (R+h) (Pythagorean theorem)
- |>
- |> 2 2
- |>d = sqrt( (R+h) - R )
- |>
- |>This says that the horizon for a six-foot tall person is about
- |>3 miles away.
- |
- |But these equations would give the 'mean' horizion, shouldn't you include
- |refraction to give the 'apparent' horizion?
-
- You're not going to get much refraction in 3 miles of air.
-
- --
- Bruce Watson (wats@scicom) Tumbra, Zorkovick; Sparkula zoom krackadomando.
- ....alien language from an SF short story on a 78-RPM record I had as a kid.
-