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- From: labute@galois.math.mcgill.ca (John LABUTE)
- Newsgroups: sci.math
- Subject: Re: Can Anyone Solve this?????
- Message-ID: <1993Jan26.174333.17703@sifon.cc.mcgill.ca>
- Date: 26 Jan 93 17:43:33 GMT
- References: <1993Jan23.210732.19327@magnus.acs.ohio-state.edu> <1993Jan24.234937.12223@galois.mit.edu>
- Sender: news@sifon.cc.mcgill.ca
- Organization: McGill University
- Lines: 15
- Nntp-Posting-Host: galois.math.mcgill.ca
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- The most elementary way to solve the differential equation y''-2y+y=0 is
- to introduce the differential operator D = d/dx. The equation then
- becomes (D^2 - 2D + I)(y) = 0 where I is the identity operator. Factoring
- the polynomial in D the equation becomes (D - I)^2(y) = 0 which is
- equivalent to the equation D^2(e^{-x}y) = 0 from which follows
- e^{-x}y = a+bx and hence y = ae_x + bxe^x. These techniques only require
- linear algebra (algebra of linear operators) and elementary calculus and
- can easily be generalised to solve any constant coefficient n-th order
- linear differential equation.
-
- --
- John Labute Phone: (514) 393-3819
- Mathematics Department FAX: (514) 398-3899
- McGill University e-mail: labute@math.mcgill.ca
-