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- Newsgroups: sci.math
- Path: sparky!uunet!spool.mu.edu!agate!linus!linus.mitre.org!gauss!bs
- From: bs@gauss.mitre.org (Robert D. Silverman)
- Subject: Re: Distribution of primes mod 4
- Message-ID: <1993Jan21.141800.17997@linus.mitre.org>
- Sender: news@linus.mitre.org (News Service)
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- Organization: Research Computer Facility, MITRE Corporation, Bedford, MA
- References: <winer.727385758@husc.harvard.edu> <PCL.93Jan21100948@rhodium.ox.ac.uk> <ARA.93Jan21081239@camelot.ai.mit.edu>
- Date: Thu, 21 Jan 1993 14:18:00 GMT
- Lines: 36
-
- In article <ARA.93Jan21081239@camelot.ai.mit.edu> ara@zurich.ai.mit.edu (Allan Adler) writes:
- >
- >How would one formulate and prove analogous theorems for primes in
- >arithmetic progressions other than 4n+/-1, 6n+/-1? One could take
-
- stuff deleted....
-
- >In view of all this potential generality, is 4n+/-1, 6n+/-1 really
- >the state of the art?
-
- Knapowski and Turan have settled special cases, but the question
- of sign changes for pi(x,a1,b) - pi(x,a2,b) a1 != a2 mod b
- for general a1,a2, and b, is still wide open.
-
- N.B. pi(x,a,b) == #{n <= x; n is prime and congruent to a mod b}
-
- It can be shown that pi(x,1,4) - pi(x,3,4)
-
- (a) changes sign infinitely often
- (b) in an appropriate sense is positive as often as it is negative.
-
- The way to interpret (b) is as follows:
-
- let u(x) = #{n <= x; pi(n,1,4) < pi(n,3,4)}
-
- Then one would expect that u(x) = x/2 for almost all x. That is to say,
- for large x, about 1/2 the integers less than x have pi(n,1,4) < pi(n,3,4)
- and for about 1/2 the integers the inequality is reversed. This can be
- made more precise;
-
- u(x) = x/2 + O(x^{1-epsilon}) for any fixed epsilon.
- --
- Bob Silverman
- These are my opinions and not MITRE's.
- Mitre Corporation, Bedford, MA 01730
- "You can lead a horse's ass to knowledge, but you can't make him think"
-