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- Newsgroups: rec.folk-dancing
- Path: sparky!uunet!charon.amdahl.com!amdahl!rtech!decwrl!ames!agate!stanford.edu!lucid.com!karoshi!fy
- From: fy@lucid.com (Frank Yellin)
- Subject: Re: Square Dance Algebra
- In-Reply-To: wex@cs.ulowell.edu's message of 27 Jan 93 16:22:24 GMT
- Message-ID: <FY.93Jan27121614@hardwick.lucid.com>
- Sender: usenet@lucid.com
- Organization: Lucid, Inc., Menlo Park, CA
- References: <fred-mckenzie-190193163934@k4dii.ksc.nasa.gov>
- <1jpvatINNih5@roundup.crhc.uiuc.edu> <30127@oasys.dt.navy.mil>
- <1993Jan26.184349.5036@adobe.com> <C1ItHC.145@ulowell.ulowell.edu>
- Date: 27 Jan 93 12:16:14
- Lines: 40
-
-
- |> Give each call a point value corresponding to its level. A Basic call is one
- |> point, Mainstream 2, Plus 3, Advanced 4, C1 5, C2 6, C3 7, C4 8.
-
- After a little bit of work, I've managed to get it down to the following
- three calls:
-
- swing-thru Mainstream = 2
- in-roll circulate Advanced = 4
- u-turn back. Basic = 1
-
- > Another interesting question is "How few total calls can you get away with?"
- > Limit the world of discourse to Advanced and lower. The best I can do it
- > with is 3.
-
- I can prove that three is the minimum. Warning, the following proof uses
- elementary group theory.
-
- Every wave->wave call can be broken down into the following three steps:
-
- (1) Perform a 4-person (element of S4) permutation on each wave.
- (2) Swap zero or more dancers with their opposites.
- (3) Optionally invert the "mirror" bit, indicating a left-hand wave and
- that everything should be looked at in the mirror.
-
- Each of (1), (2), and (3) has a parity.
-
- (1) Is the permutation even or odd.
- (2) Is the number of dancers swapping even or odd?
- (3) Is the bit unchanged or changed?
-
- Note that even though (1) and (2) do not commute with each other, their
- parities do. And (3) is completely independent.
-
- So 2 x 2 x 2 is a subgroup of the group of all call transformations. And
- 2x2x2 cannot be generated by two elements.
-
- -- Frank Yellin
- fy@lucid.com
-
-