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- From: system@cc.usu.edu
- Newsgroups: sci.physics.fusion
- Subject: electrostatic fusion
- Message-ID: <1992Dec29.112835.62319@cc.usu.edu>
- Date: 29 Dec 92 11:28:35 MDT
- Organization: Utah State University
- Lines: 671
-
- Introduction: Researchers at Hill Air Force Base have recently
- submitted a patent application concerning the use of electrostatic
- devices for creating nuclear fusion. On Dec 7, an announcement
- appeared on the network about using electrostatics for controlling
- nuclear fusion. We are making this disclosure in order to clarify
- our contribution to these developments.
-
-
-
- Obtaining Nuclear Fusion
- Using Electrostatic Devices
-
- Lloyd G. Allred, Ph. D.
- Software Support Division
- Hill Air Force Base, Utah
-
- 1. Executive Summary.
-
- 1.1 Overview. The announcement of cold fusion by Stanley Pons and
- Martin Fleishmann is probably the most controversial scientific
- claim of this century. Pons and Fleishmann felt that their
- experience in electrochemistry gave them the unique ability to
- concentrate electric fields, and that fusion was the result of this
- claim. While Pons and Fleishmann were widely acclaimed in the
- field of electrochemistry, mainstream physicists were quick to
- condemn Pons and Fleishmann's work, even though their experimental
- results have not yet been explained. This document presents
- underlying physical principals which will explain the results of
- Pons and Fleishmann, and describe how to build practical devices to
- produce large amounts of power from nuclear fusion on a repeatable
- basis. This document also explains why prior researchers have been
- unable to get repeatable results.
-
- It is interesting to note that the main thrust of the experiments
- and apparatus of Pons and Fleishmann was directed more toward
- charging up the palladium rods with positive deuterium ions. The
- issue of electric field focusing was ignored. In particular,
- electrostatic fields are focused by putting sharp points on
- electrostatic objects. The sharp points produce enormous fields.
- In the phenomena known as Saint Elmo's fire, a corona is observed
- at the edges of leaves where the charge on the leaves leaks off
- into the surrounding atmosphere. The observed corona is caused by
- the ionization of the air caused by the electric field
- concentration. Returning to the experiments of Pons and
- Fleishmann, the sharp points on the palladium rods were smoothed
- off when an explosion occurred. The two experimenters may have
- thus eliminated the very effect they were trying to create.
-
- 1.2 Approach. Some two years ago, I made the conjecture that cold
- fusion could be induced by focusing electric fields using
- electrostatic devices, in particular, that electric fields at the
- corners of such devices could be made sufficient to induce
- thermonuclear fusion. It seemed to me that it would be relatively
- simple to solve for the electrical fields surrounding a pointed
- object, such as a cone. After researching this field, I quickly
- came to the conclusion that the general solution of electrostatic
- fields is one of the unsolved problems of modern physics. While
- the study of electrostatic fields is a required subject in most
- college physics classes, the published solutions, using Gauss's
- law, have been solved only for very simplified cases. The
- published solutions for a charged wire and a cylinder violate the
- underlying assumptions, and are essentially wrong!
-
- 1.3 Summary. It has taken me some two years to find a method
- which would solve this problem. The results indicate that electric
- fields, sufficient to cause nuclear fusion, can be obtained using
- a cone with a half angle of 15 to 20 degrees, and using rather
- moderate positive
- voltages.
-
- 1.4 Claims. I claim the right to all thermonuclear fusion devices
- which employ charging a metal with deuterium and which apply an
- electrostatic charge (e.g. positive voltage) to the metal, and
- which use a pointed tip to focus the electrostatic fields. I also
- claim the rights to the process of fuzzy genetic algorithms for
- solving the charge distribution associated with a arbitrary
- electrostatic objects and for applications of such solutions. I
- also offer the U.S. American government free use of this idea, but
- reserve all applications in the private sector.
-
- 2. Theory. This document is provided without references. The
- underlying physics can be found in any college physics textbook or
- physics handbook.
-
- 2.1 Electrostatic Charges. Coulomb's law portrays the force, F,
- exerted between two electronic charges, q and q0, at spacial
- positions X and X0 and can be computed by
-
- - q q0 (X - X0)
- F = ________________ (1)
- 3
- e0 │ X - X │
-
- Coulombs law can be extended to calculate the electric potential or
- voltage of any point in space.
-
- 1 - rho(X) dS
- V = ________ Integral ________________ (2)
- S
- 4 pi e0 │ X - X │
-
- Electric potential is closely related to potential energy. In
- particular, it expresses the amount of potential energy per unit of
- charge for at any point in space. The electric field is defined as
- the gradient of the electric potential,
- partial V 1 rho(X) (X-X0) dS
- E = _________ = _______ Integral ________________ (3)
- 3
- partial X 4 pi e0 S │ X - X0 │
-
- In the presence of a non-zero electric field, a charged particle
- will be accelerated in the direction of the field, inducing an
- electric current. At any point in the interior of a conductive
- device, the electric field must therefore be zero, otherwise, any
- electron at that point would be accelerated, thus changing the
- distribution of the electric charges and the corresponding electric
- fields and the electric fields would not therefore be static. At
- the surface of a conductive device, an electric field can be
- resolved into two components, one parallel to the surface, and one
- perpendicular to the surface. The parallel component must be zero
- (otherwise a current would be generated parallel to the surface of
- the conductor), hence the electric field must be perpendicular to
- the surface of the charged conductive object.
-
- Gauss's law relates the integral of an electrostatic field over an
- arbitrary surface to the enclosed charge.
- 1
- _______ Integral E . dA = Q (4)
- 4 pi e0 A
-
- This equation can be employed to produce some very strange results.
- Electric charges in a charged conductor tend to repel each other.
- As a result, they get as far away from each other as is possible.
- Taking a surface just inside the charged device, the above equation
- implies that the enclosed charge is zero! As a consequence, the
- charge must be distributed entirely on the surface of the object.
- Additionally, the charge density at the surface is directly
- proportional to the electric field over the surface. If one
- considers a surface consisting of two connected parallel plates,
- both parallel to the surface with one above the surface, and one
- below. Because the one below the surface is inside the metal, the
- electric field is zero. It follows that
- 1
- _______ Integral E . dA = Q = rho dA (5)
- 4 pi e0 A
-
- Consequently
-
- E = rho 4 pi 0 (6)
-
-
- For an electrostatic object of a cone, we intend to show that the
- electric field approaches infinity as one approaches the tip of the
- cone. Because the charge density at the tip is proportional to the
- electric field at the tip, then, byt the above equation, the charge
- density also approaches infinity. If the charges consist of
- positively charged deuterium ion,s then nuclear fusion will occur.
-
-
- 2.2 Supportive Evidence. In the phenomena known as Saint Elmo's
- fire, a corona is observed at the edges of leaves where the charge
- on the leaves leaks off into the surrounding atmosphere. The
- observed corona is caused by the ionization of the air caused by
- the electric field concentration.
-
- Some metals, such as platinum, palladium, titanium, and nickel have
- the ability to absorb large amounts of hydrogen and deuterium.
- After absorption, the hydrogen nucleus and electron separate. An
- ionized hydrogen nucleus, having no shell, is free to wander
- throughout the metal in the same manner as a free electron. If the
- conductive metal becomes positively charged, the hydrogen nuclei
- will congregate at the sharp points of the surface, and be ejected
- from the surface. It was trace amounts of tritium and helium,
- observed by Russian scientists in nickel deposits, which first
- prompted the initial investigations into cold fusion.
-
- 2.3 "Antimatter". In the past, electric field confinement has
- been rejected as a method for obtaining fusion. In particular, a
- theorem exists that a charged particle cannot be confined by an
- electrostatic field. In practice, confinement is not required.
- One example is the production of fusion obtained by imploding
- spheres of frozen hydrogen. While confinement is not achieved in
- this process, the imploding deuterium nuclei come crashing into
- each other. The resulting fusion has been observed in the
- laboratory; unfortunately, however, the resulting fusion has not
- been not sufficient to achieve a positive energy return.
-
- 3.0 Proposed Mechanics. I fully understand that infinite
- electrical fields are an impossibility. As a consequence, static
- conditions cannot be achieved on an object with a tip because the
- charge leaks off into empty space. The charge at such a tip will
- be less than
- infinite. However, as the subsequent discussions will show, the
- electric fields at the tip are caused by the focusing of the
- electric fields of charges away from the tip. As a result, the
- charged particles within the device will be accelerated toward the
- tip─these accelerations approach infinity as the charges move
- toward the tip. Inasmuch as fusion has been produced by
- accelerating protons together by implosion, it would seem that
- fusion could be obtained by accelerating protons together by
- focusing electric fields. In the case of the cone, the charges are
- all concentrated on the surface of the cone. As a consequence, the
- electric fields are all
- directed towards the tip of the cone. If the metal contains
- positively charged hydrogen ions, they will be accelerated toward
- the tip. Electric currents move at the speed of light. While the
- individual electrons and protons will move at speeds somewhat less
- than the speed of light, I suspect the accelerations, even at short
- distances, are enormous. I would be greatly surprised
- if fusion did not occur.
-
- 3.1 Caveats. Surface conditions would be very critical to this
- process. Rough surfaces would tend to leak the hydrogen off.
- Smooth surfaces seem to be a rudimentary requirement in existing
- cold fusion experiments. Metals such as titanium and aluminum form
- an oxide coating─I suspect that protons may not be the principal
- charge carriers on the surface of these metals, perhaps explaining
- the failure to produce positive cold fusion results using these
- metals. While hydrogen absorption and the corresponding metal
- embrittlement is observed in many metals, much better absorption
- characteristics are obtained using nickel, palladium, and platinum.
-
- 4. Problem Solution.
-
- 4.1 Traditional Analytical Methods. College textbooks usually
- employ Gauss's equation to solve for the distribution of charge on
- a surface. For a sphere, for example, one can argue, by symmetry,
- that the electric field is equal for all points of the sphere.
- Gauss's equation reduces to
- 1 E 4 pi R R
- _______ Integral E . dA __________ = Q (7)
- 4 pi e0 A 4 pi e0
-
- Solving for the electric field, E,
- Q e0
- E = ____ (8)
- 2
- R
-
- For applications to objects such as an electrical wire, the
- textbooks say, "assume that the charge density is distributed
- equally along the length of the wire". We could equally assume
- that the world is flat, or that we have a spherical cow.
-
- If one had such a charge distribution along a wire, compute the
- electric field at a point on the left side of the wire. Applying
- Equation (3) to our example of a wire of length extending in x
- direction,
- 1 1 rho(x) (x-x0) dS
- E = ________ Integral ________________ (9)
- 3
- 4 pi e0 0 │ x - x0 │
-
-
-
- The integral splits into two parts, one for x < x0 and x > x0.
- Substituting x = t + x0,
-
- x0 rho(x0-t) dt 1-x0 rho(x0+t) dt
- Integral ____________ = Integral _____________ (10)
- 0 2 0 2
- t t
-
- The above equations pointedly illustrate the problems with
- attempting to deal with charged particles using traditional math.
- The above two integrals are both infinite! Solution of Equation
- (9) to get a zero electric field requires the subtraction of two
- infinities. To obtain practical solutions to Equation (11)
- requires that we treat the electric densities in terms of
- individual charges, and that the electric field, acting on each
- charge, approaches zero. Taking this point of view, individual
- charges are separated by a minimal subatomic distance, m. The
- above equation becomes
-
- x0 rho(x0-t) dt 1-x0 rho(x0+t) dt
- Integral ____________ = Integral _____________ (11)
- m 2 m 2
- t t
-
-
- For uniform density, the above equation cannot be met unless x0 =
- 1 - x0, or x0 = 0.5, at the midpoint on the wire. For a point on
- the left of the midpoint of the wire, there is more total charge on
- the right side of the wire, so the electric field points to the
- left. The bottom line is that the charge distribution along a
- fixed wire cannot be uniform.
-
- What is the charge distribution along a wire? As x0 decreases, the
- integration distance of the left integral decreases, so the
- corresponding values of ■ must increase to compensate. Conversely,
- the integral on the right, Ir must increase. Not only does the
- integration distance increase, but as x0 increases, the integral on
- the right begins to incorporate some of those increased ■ values
- which were created to compensate for increases in Ir for slightly
- larger values of x0 and so forth. Applying the mean value theorem
- of integral calculus to the above equation, there exist some point
- xL, 0 ≤ xL ≤ x0.
-
- x0 rho(x0-t) dt
- Integral ____________ = Ir (12)
- m 2
- t
-
- Integrating,
-
- rho(XL) (-1/x0 + 1/m) = Ir (13)
-
- Collecting terms,
-
- rho(xL) = m x0 Ir / (x0 - m)
-
- As x0 decreases toward m, the right side of the above equation
- approaches infinity. The mean value theorem of integral calculus
- states that ■(xL) can be interpreted as an average value of the
- density function rho between m and x0. As x0 decrease to m, this
- average density approaches infinity! Similar arguments can be
- presented for charges near the tip of the cone. Unfortunately, the
- above mathematical arguments do not provide quantitative analysis
- for the solution of the charge densities, nor can qualitative
- mathematical arguments be employed to arrive at a fixed hardware
- design.
-
- 4.2 Finite element approximations. My attempts at solving various
- forms of Equation (11) over a two year time-span met with dismal
- failure. The reasons for this failure have some interesting
- physical ramifications. Suppose that one attempts some finite
- approximation to Equation (11) with a number of charges at fixed
- positions, then the failure to achieve zero in Equation (11) can be
- interpreted as a force on the individual charge. I attempted to
- solve the equations through gradient search techniques, equivalent
- to move each charge according to the applied force. As one moves
- toward the tip of the wire, the forces become infinite, and the set
- of simultaneous equations becomes unstable and will not converge!
- The tracking of the individual charges is equivalent to solving for
- the standing waves of the individual electrons on the wire.
- Standing waves in a conductive media are real physical phenomena;
- unfortunately, the standing waves have little to do with the
- electrostatic solution we seek.
-
- After many attempts at solving the electrostatic fields surrounding
- a pointed cone, I was able to obtain a solution by modifying a
- method proposed by a Dr. Magdy K. Iskander of the University of
- Utah [Electromagnetic Fields, Prentice Hall]. Iskander's method
- approximates the electric potential in Equation (2) by a finite
- sum, by evaluated at a finite number of points, X1,...,Xn.
-
-
- By definition, the voltage potential, V, is constant for any point
- on the conductor. For a fixed selection of n points,
- ■(Y1),■(Y2),...■(Yn), the above formula will generate a linear
- equation for
- any point Xi within the conductive object. The resulting equations
- are linear in the ■(Yj) and
-
- 1 n - rho(Yj) dSj
- V = ________ Sum ________________ (2)
- j=1
- 4 pi e0 │ X - X │
-
- can be solved by traditional linear equation methods. The
- resulting solution for a charged wire, published by Iskander,
- conforms to my solution, Equation (14). Unfortunately, the method
- is highly sensitive to the selection of the X's and the Y's. In
- particular, the X's and the Y's cannot coincide, otherwise
- numerical division errors occur. In addition, finite
- approximations are not exact, so the voltages resulting from the
- finite approximation are not uniform across the object. As one
- increases the number of elements, the equations become singular,
- and cannot be solved. While able to reproduce Iskander's results,
- I was not able to refine the results by taking smaller step sizes
- for a charged wire. I was also unable to apply the technique to
- surfaces of revolution, such as spheres and cones.
-
- 5.0 Solution Using Self-Organizing Systems. Over the past four
- years, my software group, the Neural Engineering Research and
- Development Section (NERDS) have been solving difficult problems
- using self-organizing systems. One such method employs a fuzzy
- differential genetic algorithm. During a simulation, individuals
- are created with genetic code which is represented as binary bits.
- The binary bits are interpreted as the distribution of charges
- along the cone. Using this charge distribution, the voltage is
- then calculated at various points on the cone, and an individual's
- fitness is evaluated based on how uniform the resulting voltage
- potential is. Using simulated natural selection individuals are
- selected to breed (survival of the fittest), and using simulated
- sexual reproduction succeeding generations of individuals are
- generated. Through the process of simulated natural selection, an
- individual is found which solves the charge distribution along the
- cone.
-
- The fuzzy genetic algorithm was able to obtain solutions to the
- electrostatic charge for a variety of physical shapes. Equilibrium
- is achieved as the voltage approaches uniformity across the shape's
- surface. (See attached figures). In roughly 15 minutes, the
- program will solve for the charge distribution for an arbitrary
- surface of revolution. Validation of the software was achieve by
- solving for the known charge distribution for a sphere.
-
- For objects containing tips, such as wires and cones, the electric
- fields approached infinite as one moves toward the tips. While
- mathematical techniques may prove that the charge density
- approaches infinity as one approaches the tip of the cone, the
- mathematical techniques offer no clue toward finding an optimal
- cone design. The fuzzy genetic algorithm was employed to solve for
- the charge distribution for a variety of cone angles, giving
- effective delivered proton compression for each shape. Simulations
- for an optimized cone shape are presented in the next section.
-
- 6.0 Engineering Considerations for Building a Prototype.
-
- Some metals, such as platinum, palladium, titanium, and nickel have
- the ability to absorb large amounts of hydrogen and deuterium.
- After absorption, the hydrogen nucleus and electron separate. The
- lone proton (or paired proton/neutron) separate. An ionized
- hydrogen nucleus, having no shell, is free to wander throughout the
- metal in the same manner as a free electron. Titanium is not
- recommended because of surface conditions involving titanium oxide.
- Metal oxides are generally poor conductors of electricity, and the
- oxide will probably limit the ejection of protons from the cone's
- surface.
-
- An electrolysis process is involved (shades of Pons and Fleishmann)
- to saturate the metal of the cone with hydrogen. During this
- process, a slight negative voltage should be applied to the
- conductor to insure that the protons will not leave the cone. Once
- the metal is charged, a high positive voltage will be applied to
- the cone. It is recommended that the cone be mounted so that tip
- of the cone penetrates the tub of the water chamber into a second
- chamber, or be pointed upward, out of the water. We also recommend
- that the second chamber be evacuated. This is done to insure that
- the discharging of the cone be accomplished by ejection of protons,
- and not by the ionization of molecules which happen to reside at
- the tip of the cone. Obtaining nuclear fusion requires more than
- intense electric fields. It also requires that two protons be
- force toward each other with sufficient velocity to overcome the
- repulsion of the two particles. In the sun, it is achieved by
- temperatures of millions of degrees. It has also been achieved in
- particle accelerators, and by imploding frozen hydrogen pellets.
-
- Suppose that one has a cone charged up with deuterium ions.
- Applying a positive voltage pulse to the cone, deuterium ions will
- be accelerated toward the tip. When the particle densities exceed
- critical values, deuterium ions will be ejected from the tip,
- causing disequilibrium. Protons inside the cone will be
- accelerated toward the tip at enormous velocities. As they
- approach the tip, the magnitude of the acceleration will approach
- infinity because the electric field at he tip are caused by the
- focusing of the electric fields of charges away from the tip. The
- protons will therefore implode at the tip of the cone.
-
- Consider two deuterium ions, being ejected from the cone at the
- same time from opposite directions. If the cone is pointed up,
- then the vertical velocities of each deuterium ion will be the
- same, and it would appear, relative to each ion, that the other ion
- is headed directly toward it. It is a fairly straight forward
- application of classical physics that if the accelerations are
- strong enough, then sufficient velocities can be achieved to cause
- nuclear fusion, similar to that which occurs in more traditional
- particle accelerators.
-
- It is here that we deviate from traditional attempts of cold
- fusion. To increase the acceleration of the charged particles
- requires that we increase the magnitude of the applied voltage.
- The applied voltage can be scaled up considerably using
- conventional voltage amplification devices or electronic pulsers.
- (This has not been attempted in traditional cold fusion
- applications). It is also important that material be evacuated
- from the tip of the cone either by penetrating the side of the
- water bath, or by pointing the cone upward out of the water bath.
- In particular, the ionization of the water will provide electrons,
- which when attracted toward the cone, neutralizing the positive
- charge of the cone, and mitigating the effect we are trying to
- produce. This has not been attempted in traditional cold fusion
- applications. In addition, we are reconfiguring the geometry by
- using pointed shapes as opposed to smoothed shapes. The angle of
- the point must be optimized to produced the maximal result.
-
- Although the electric fields become very large for a variety of
- cone shapes, the delivery of an infinite electric field will be
- mitigated by errors in cone geometry and by charge leakage at the
- tip. To compare the effectiveness of the various geometries, we
- compute a delivered electric field as the electric field at a point
- a slight distance from the tip, namely at a distance 1% of the
- length of the cone. Returning our attention to the two deuterium
- ions being ejected from the cone at the same time, the
- accelerations on the two ions have two components─one component
- accelerates them in the same direction, the other accelerates them
- toward each other. The effective implosive force per charge is the
- effective acceleration per charge toward each other is the
- delivered electric field times the cosine of the cone angle. A
- plot of effective implosive force for a variety of cone shapes is
- presented in the figure. The optimal half-cone angle is about 15
- deg.
-
- Compromises for practical device construction will involve rods
- made of nickel or palladium which will have one end spherically
- rounded and the other end to be ground down to a 15 deg point. Our
- results with wire simulations show that increasing the length of
- the rod increases the electric field at the end.
-
- At present we have many ideas for improvement of the basic design,
- ideas for energy recovery, and so forth. These ideas can wait
- until we prove the basic feasibility.
-
-
- Lloyd G. Allred
- 26 Oct 92
-
-
-
-
-
-
- Lloyd G. Allred
- OO-ALC/TISAA
- Hill AFB, Utah 84056
-
- Electrostatic Field Computations
-
-
- Don Baker
- Los Alamos National Laboratory
-
- 1. Thank you for your review and comments regarding electrostatic
- fields. You raise some interesting points. I do not claim to have
- all of the answers. What I am hoping to do is shed some light on
- some obscure aspects of physics and suggest some experiments which
- might have some unusual outcomes. With this in mind, I will
- attempt to address some of the points you have made, and suggest
- some further investigations.
-
- 2. Since the electrostatic fields are normal to the surface won't
- the particles be emitted in the high field region before reaching
- the point? I am reasonably confident that particle emissions will
- be a significant factor in these processes. This is just as well,
- as we are not trying to make a 20 megaton bomb. The issue here is
- will the density at the tip be sufficient to induce nuclear fusion?
- I think the hypothetical equilibrium solution for a static
- conditions sheds some light on this subject. The solution predicts
- infinite density for static conditions. You and I both know that
- infinite density cannot be achieved─other processes, such as
- emission, etc., will intervene to mitigate these factors. The
- question I raise is as follows: during the attempt of the system
- to achieve equilibrium, will the induced fusion be sufficient to
- achieve a positive energy return?
-
- 3. ... fusion cross-sections have not been measured below 5
- Kev...Since the particles get their energy from an electrostatic
- field, they must fall through potentials equal to the kinetic
- energies required. How do you explain the positive results in
- previous cold fusion results using low voltages? What you analysis
- does suggest, however, is that we include in our design the ability
- to crank up to 20 kilovolts. I should point out that when
- inductances are considered, that net particle accelerations can
- exceed the applied voltages. A similar effect can be observed with
- the earth's tides which raise the sea level some six feet. There
- are certain bays and fjords which focus the tidal energy, producing
- tides in excess of 20 feet. This effect is observed
- electronically, when a voltage pulse is sent down a wire. When the
- pulse reaches the end of the wire, it is reflected, thus doubling
- the voltages. When one considers a collection of positive ions
- converging on the tip, and the associated reflections, the
- resulting energies will exceed the amount computed by falling to
- the potential of the nominal applied voltage.
-
- 4. ...one must overcome ... the Coulomb barrier ... before ...
- tunneling becomes appreciable. My experience with electronic
- response of zener diodes has taught me that tunneling is probably
- the controlling factor in most barrier phenomena. I do not see why
- Coulomb barrier potential should be exceptional. I suspect that
- the traditional M.I.T. sledge-hammer approach to fusion may have
- overlooked the more subtle effects of tunneling─including the
- initial energy of Helium 4 nucleas and the resulting decay. This
- could be a whole new ball game.
-
- 5. Is it clear that the hydrogen isotopes can be highly
- accelerated through the lattice? Won't they be impeded by
- collisions? In Rutherford's seminal work on particle physics, he
- bombarded a thin metal foil with a stream of protons. Proton
- deflections were extremely rare events. These experiments showed
- that matter consists of mostly empty space. To a positively
- charged proton, the interior of the metal appears to be so much
- empty space. Won't the protons be impeded by collisions? Oh God!
- I hope so. May be we'll get some fusion when they collide!
-
- 6. I would like to know more about the calculation method. In
- the classical electrostatic case, the problem is represented as a
- problem in genetics. Individuals are created at random; their
- genetic material is interpreted as a potential solution to the
- electrostatic problem. Through a process of simulated natural
- selection and simulated reproduction, succeeding generations
- ofindividuals are created which better solve the problem until a
- solution is reached. We have developed a tool which we call a
- differential fuzzy genetic algorithm which an optimize general
- problems of this kind. In many respects, the details of the
- differential fuzzy genetic algorithm are transparent to the user.
- The user need only write a procedure which evaluates how well a
- hypothetical problem solutions works.
-
- In the electrostatic problem, finite charges are distributed around
- the surface of the electrostatic device, and the electronic
- potential is calculated at points centered between the charges.
- The process is repeated until the variance of the electronic
- potential is minimized, creating electrostatic equilibrium. Our
- software program can solve the charge distribution problem for a
- general surface of revolution such as a wire, a cone, or a sphere.
- The program produces uniform distribution for a sphere, and the
- solution for the wire agrees with the published solutions. Once
- the placement of charges has been determined, one then calculates
- the electric field at the points centered between the charges. On
- obtain a set of points, x1,...,xn, with corresponding electric
- fields E1,...,En. This points can be smoothed to obtain a curve,
- y = f(x). To obtain a more accurate representation of the curve,
- one places more points in the simulation. I am not intending to
- patronize─I only want this point to be made perfectly clear. This
- fill-in-the-points process is employed in all computer-based
- representations of continuous processes. As the number of points
- approaches infinity, one approaches the continuous curve. In
- application to a 15 degree cone, the curve is y = k / x0.6. This
- curve approaches infinity as one approaches the tip of the cone.
-
- 7. A real difficulty is that the jump from ideal field
- calculations treating the conducting particles as a continuous
- fluid in a perfect conductor to a realistic quantum-mechanical
- many-body problem calculation is a long way off. No kidding. To
- my understanding, the many body problem has not been generally
- solved for simple molecules─the solutions which do exist (such as
- diatomic hydrogen) can take weeks to run on a Cray using
- traditional techniques. It might interest you to know that the
- technique which we used to solve the electrostatic problem may
- prove equally applicable to the quantum mechanical problem. In
- particular, both problems involve solving the probability
- distributions of particle placement. Using a similar method, one
- can compare various hypothetical distributions, and through a
- process of natural selection, find the one which best describes the
- problem. My experience with Schroedinger's equation shows that
- excellent solutions can be obtained by fitting the solution with
- piece-wise linear solutions to the wave equations. A similar
- approach could be obtained in application to the multi-body
- problem, or to the distribution of charges along a cone. The
- Schroedinger equation is usually solved for application where the
- electric potential is known (such as a barrier well); however, one
- could extend the method to simultaneously solve for the electric
- potential for a hypothetical placement of particles in a multi-body
- problem. While I do extra curricular work in support of students,
- various universities, and various research projects, I also have a
- large family, and I cannot afford to undertake such a task on my
- spare time. In my career plans, I never anticipated researching in
- fundamental particle physics. For a nominal fee, we could be
- persuaded. Send money. Our organization is industrially funded,
- which means that we have to find a customer to pay for our time.
- My going rate is about $200,000 per year. This includes support
- staff and equipment. These algorithms we are investigating are
- directly amenable to parallel processing; routinely solving these
- kind of problems warrants the purchase of a massively parallel
- machine.
-
- 8. One question, not using your accelerator ideas. How high a
- density can one pack the fusion particles in the pointed region in
- the static case? Good question. As I understand the process of
- hydrogen adsorption, hydrogen can be regularly distributed
- throughout the metal lattice. I have read descriptions of enormous
- adsorption capabilities of platinum, but do not have the sources at
- my disposal. I would be interested to see the actual figures.
-
-
-
- DR LLOYD G ALLRED, Technical Lead
- Neural Engineering Research and Development Support (NERDS) Team
- Aircraft Software Development Branch
- Software Engineering Division
-