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- Newsgroups: sci.physics
- Path: sparky!uunet!think.com!enterpoop.mit.edu!galois!riesz!jbaez
- From: jbaez@riesz.mit.edu (John C. Baez)
- Subject: Re: FEYNMAN GRAPH EXPANSION QUESTION
- Message-ID: <1992Dec20.221840.27537@galois.mit.edu>
- Sender: news@galois.mit.edu
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- Organization: MIT Department of Mathematics, Cambridge, MA
- References: <1h1j3cINN8tg@gap.caltech.edu> <KILCUP.92Dec20145548@einstein.mps.ohio-state.edu> <MATT.92Dec20122038@physics.berkeley.edu>
- Date: Sun, 20 Dec 92 22:18:40 GMT
- Lines: 24
-
- In article <MATT.92Dec20122038@physics.berkeley.edu> matt@physics.berkeley.edu writes:
-
- >It's worth pointing out, by the way, one reason why I don't think
- >we're ever going to see computer programs that can evaluate Feynman
- >diagrams of arbitrarily high order: once you get beyond one or two
- >loops, it requires a fair amount of ingenuity to figure out how to
- >calculate them. The method that we're all taught (Feynman- or
- >Schwinger-parameterization of the denomenator, then doing the loop
- >integral with some appropriate regularization scheme, then doing the
- >integral over the parameters) just doesn't work for more than one or
- >two loops: the integral over the parameters becomes undoable. You
- >have to be creative, and figure out some trick. See, for example,
- >T. Curtright, Phys. Rev. D21, 1543 (1980), who describes one such
- >trick for one particular three-loop diagram.
-
- Could you answer a question that I find to be utterly crucial here? Is
- this a matter of ingeniously evaluating well-defined expressions or is
- there actually some freedom of choice involved? In the
- former case, even if ingenuity is required to do the integral, one is
- essentially solving a well-posed *math* problem. In the latter case,
- one could imagine actual disagreement over the right answer - in which
- case one is really adding extra fine print to the description of the
- physical theory, not just calculating within a precisely specified theory.
-
-