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- From: martin@lyra.cis.umassd.edu (Gary Martin)
- Subject: Re: 2 questions (GRE Subject test)
- In-Reply-To: sla7@cunixa.cc.columbia.edu's message of Fri, 25 Dec 1992 04:06:17 GMT
- Message-ID: <MARTIN.92Dec25123717@lyra.cis.umassd.edu>
- Sender: usenet@umassd.edu (USENET News System)
- Organization: University of Massachusetts Dartmouth
- References: <1992Dec25.040617.26522@news.columbia.edu>
- Date: Fri, 25 Dec 1992 17:37:17 GMT
- Lines: 31
-
- In article <1992Dec25.040617.26522@news.columbia.edu> sla7@cunixa.cc.columbia.edu (Seth Louber Antiles) writes:
-
- Saw this question in a sample GRE math subject test:
-
- If f(1+x)=f(x) for all real x. If f is a polynomial and f(5)=11 then
- what is f(15/2)?
-
- In general, for f a polynomial, for what g will f(g(x))=f(x) for all x
- *not* imply that f is a constant? Appreciate simple examples.
-
- If g has an infinite orbit or finite orbits of unbounded cardinality,
- then f must be constant because the degree of f bounds the number
- of solutions to f(x) = c for any c. This suggests looking for
- functions g for which g^n is the identity function for some n.
- For example g(x) = -x. Or perhaps a finite-to-one idempotent function
- like g(x) = |x|.
-
- What if we remove the restriction that f is a polynomial?
-
- Too big a question.
-
- Another GRE question in the same sample:
-
- "No element (other than identity) is its own inverse." What does this
- tell you about a group?
-
- That it's solvable. :-)
-
- --
- Gary A. Martin, Assistant Professor of Mathematics, UMass Dartmouth
- Martin@cis.umassd.edu
-