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- Path: sparky!uunet!haven.umd.edu!darwin.sura.net!gatech!psuvax1!hsdndev!dartvax!J.Theodore.Schuerzinger
- From: J.Theodore.Schuerzinger@dartmouth.edu (J. Theodore Schuerzinger)
- Newsgroups: rec.puzzles
- Subject: Re: simple number puzzle
- Message-ID: <1992Dec22.010621.19817@dartvax.dartmouth.edu>
- Date: 22 Dec 92 01:06:21 GMT
- References: <1992Dec21.195038.28106@Csli.Stanford.EDU>
- Sender: news@dartvax.dartmouth.edu (The News Manager)
- Organization: Dartmouth College, Hanover, NH
- Lines: 43
- X-Posted-From: InterNews1.0b1@newshost.dartmouth.edu
-
- Yuzuru Hiraga writes:
-
- A simple number puzzle for Christmas...
- # sorry if this is in the FAQ: ours just expired.
-
- What positive integer cannot be expressed as a sum of 2 or more
- consecutive integers?
-
- I believe the answer is 2^n power (where n is an integer) can't be
- expressed as the sum of consecutive integers, but all other numbers
- can.
-
- **End of quoted material.
-
- Proof:
-
- 1. All odd integers can be expressed as the sum of two consecutive
- integers.
-
- 2. 4 consecutive integers will give all numbers with exactly one factor
- of 2.
-
- 3. x number of consecutive integers, where x is prime (and not equal to
- 2), will give you all multiples of x (starting at x^2+x/2).
-
- Numbers lower than (x^2+x)/2 fall into two cases:
- a) Odd numbers, covered above.
- b) Even numbers. As these have only one multiple of 2, they will
- obviously be a number that has a remainder of 2 when divided by 4 (ie.
- case #2 above).
-
- This solves all numbers except for those whose only factors are 2 (ie.
- powers of 2).
-
- As I am leaving to go home for Christmas tomorrow morning, anyone who
- has the rest of the proof should email me directly with it.
-
- Thanks!
-
- --Ted Schuerzinger
- email: .zed@Dartmouth.EDU
- "I should have known it would be bad vodka when all the label said was
- 'Russian Vodka'."
-