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- Path: sparky!uunet!newsflash.concordia.ca!mizar.cc.umanitoba.ca!access.usask.ca!skorpio!choy
- From: choy@skorpio.usask.ca (I am a terminator.)
- Newsgroups: k12.ed.math
- Subject: Re: Math prob...
- Date: 29 Dec 1992 00:08:04 GMT
- Organization: University of Saskatchewan, Saskatoon, Canada
- Lines: 47
- Sender: choy@skorpio (I am a terminator.)
- Distribution: world
- Message-ID: <1ho4t4INNl3c@access.usask.ca>
- References: <33017.2B3AC0F2@puddle.fidonet.org>
- NNTP-Posting-Host: skorpio.usask.ca
-
- In article <33017.2B3AC0F2@puddle.fidonet.org>, Lloyd.Johnston@p0.f45.n342.z1.fidonet.org (Lloyd Johnston) writes:
- |> EG> Here is a problem I don't really understand how the result is
- |> EG> reached.
- |> EG> Prob. sqrt(y) + sqrt(y+5) = 5
- |> EG> Ans. y=4
- |> EG> I see that if you just pop in 4 you get 2+3=5.
-
- The solution to an equation is the set of values that y can be substituted
- with to make the STATEMENT sqrt(y) + sqrt(y+5) = 5 TRUE.
-
-
- |> however I thought
- |> EG> that sqrt(y+5) was the same as sqrt(y) + sqrt(5) giving y=10
-
- SUPPOSE that sqrt(y+5) = sqrt(y) + sqrt(5). Then we can claim
- sqrt(1 + 5) = sqrt 1 + sqrt 5 = 1 + sqrt 5 = sqrt 6. But we KNOW that
- sqrt 6 is NOT 1 + sqrt 5. So we have found that sqrt(y+5) is NOT equal
- to sqrt(y) + sqrt(5), at least, not in GENERAL.
-
- But you can see that sqrt(y+5) = sqrt(y) + sqrt(5) is an EQUATION.
- What is the solution to the equation?
-
- Is the solution the set of nonnegative real numbers?
-
- Note: sqrt(5y) = sqrt 5 x sqrt y for all nonnegative y.
-
- --
-
- Henry Choy
- choy@cs.usask.ca
-
- "The Log Song", from Ren & Stimpy
-
- "What rolls down stairs alone or in pairs
- Rolls over your neighbor's dog?
- What's great for a snack and fits on your back?
- It's Log, Log, Log!
-
- It's Log, Log, it's big, it's heavy, it's wood.
- It's Log, Log, it's better than bad, it's good!
- Everyone wants a log! You're gonna love it, Log!
- Come on and get your log! Everyone needs a Log!"
-
-
- "Math is tough!"
-
- -- Barbie
-