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- From: lwloen@rchland.vnet.ibm.com (Larry Loen)
- Subject: Re: GNU Chess ratings estimates...
- Sender: news@rchland.ibm.com
- Message-ID: <1992Dec30.225921.11082@rchland.ibm.com>
- Date: Wed, 30 Dec 1992 22:59:21 GMT
- Reply-To: lwloen@rchland.vnet.ibm.com
- Disclaimer: This posting represents the poster's views, not necessarily those of IBM
- References: <1992Dec29.170710.9011@leland.Stanford.EDU> <1992Dec29.132902.27546@crash> <1hqp39INNilh@shelley.u.washington.edu>
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- In article <1hqp39INNilh@shelley.u.washington.edu>, monaghan@cac.washington.edu (Tracy Monaghan ) writes:
- |>
- |> Thanks for the formula for estimating GNUchess strength, but...
- |>
- |> For those of us who are mathematically-deficient, is there a formula
- |> which doesn't use log2 but makes use of log10, or ln (natural log), or
- |> barring that, some fanciful way of achieving log2 using log10 and/or ln?
- |>
- |> Or, if someone just happens to know the estimated rating of GNUchess 4pl60
- |> on a DECstation 3100...
-
- The conversion is available in a lot of mathematics books. If memory serves,
- converting works as follows:
-
- x = log to base 2 of (some expression or other).
-
- x*ln(2)/ln(10) produces the value of x as a base 10 logarithm.
-
- If y is not "logged" yet. That is:
-
- y = (some expression or other)
-
- then the base 10 logarithm is it is ln(y)/ln(10)
-
- where "ln(z)" is the natural log of z.
-
-
- Anyway, that's what MS DOS basic shows me.
-
- --
- Larry W. Loen | My Opinions are decidedly my own, so please
- | do not attribute them to my employer
-