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- From: sichase@csa3.lbl.gov (SCOTT I CHASE)
- Newsgroups: sci.physics
- Subject: Re: Calculation of G
- Followup-To: sci.physics
- Date: 23 Nov 1992 12:24 PST
- Organization: Lawrence Berkeley Laboratory - Berkeley, CA, USA
- Lines: 39
- Distribution: world
- Message-ID: <23NOV199212243715@csa3.lbl.gov>
- References: <1992Nov5.001719.20068@cs.rochester.edu> <1992Nov8.211900.18937@isus.UUCP> <9NOV199212382504@csa2.lbl.gov> <1992Nov22.213716.19071@isus.UUCP>
- NNTP-Posting-Host: 128.3.254.198
- Keywords: Reciprocal System, Derivation of gravitational constant
- News-Software: VAX/VMS VNEWS 1.41
-
- In article <1992Nov22.213716.19071@isus.UUCP>, hoyt@isus.UUCP (Hoyt A. Stearns jr.) writes...
- >In article <9NOV199212382504@csa2.lbl.gov> sichase@csa2.lbl.gov (SCOTT I CHASE) writes:
- >>>G can be calculated from basic Reciprocal System principles to
- >>> the minimum accuracy of the three numbers used as a starting point:
- >>> c, Avogadro's number, and the Rydberg frequency.
- >>>
- >>Would you please demonstrate a derivation of G from this data?
- >>
- >Here is a derivation:
-
- [...Derivation omitted...]
-
- This was interesting, but you have not presented it in a way that I
- could follow completely. I'll try to extract the essentials. You
- say that:
-
- >So G<cgs> = 3N/Mc^3 = 6.66559478 E-8 dyne-cm^2/g^2
-
- So naturally, I looked back in your proof to find the values of M and N.
- I found:
-
- >Define M the mass in amu of a natural unit of mass.
- >M = 1 + 1/(128*(1+2/9)) = 1.00639205 amu.
-
- So far so good. But when I tried to find out how N is defined, all
- I got was:
-
- >1 mole of natural mass units = M grams<cgs>
- ># M/N (unit-mass<gram>/unit-mass<nu>).
-
- What does this mean?
-
- -Scott
- --------------------
- Scott I. Chase "It is not a simple life to be a single cell,
- SICHASE@CSA2.LBL.GOV although I have no right to say so, having
- been a single cell so long ago myself that I
- have no memory at all of that stage of my
- life." - Lewis Thomas
-