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- Newsgroups: sci.physics
- Path: sparky!uunet!snorkelwacker.mit.edu!galois!riesz!jbaez
- From: jbaez@riesz.mit.edu (John C. Baez)
- Subject: Re: Irregular wave motion results
- Message-ID: <1992Nov20.221432.23127@galois.mit.edu>
- Sender: news@galois.mit.edu
- Nntp-Posting-Host: riesz
- Organization: MIT Department of Mathematics, Cambridge, MA
- References: <1992Nov18.105130.17567@husc15.harvard.edu>
- Date: Fri, 20 Nov 92 22:14:32 GMT
- Lines: 34
-
- In article <1992Nov18.105130.17567@husc15.harvard.edu> blom@husc15.harvard.edu writes:
- >I wrote a simple computer program to simulate waves in a cable fixed at both
- >ends as if that cable were a number of springs joined together (320 springs, to
- >be exact). I expected to see motion like that predicted by classical wave
- >mechanics, obeying the wave equation
- >
- >d2y 2 d2y
- >--- = v ---
- >dt2 dx2
- >
- >from which we find that the shape of a travelling wave pulse does not change
- >over time. It occurs to me, though, that this should only work for analytic
- >functions. What happens to places on a pulse where the wave comes to a point?
- >(i.e. where the function has no definable derivative)
-
- Well, this is one reason why people invented distributions and the
- notion of "distributional derivatives". Using these concepts the wave
- equation still makes sense at nasty points such as you describe.
-
- If you're not up to learning distribution theory, there's a cheap way
- out, since your equation is easy to solve exactly. The general solution
- is a sum of left- and right-moving waves, i.e. f(x-vt) and g(x+vt).
- Here f and g are ANY function and need not be smooth or even continuous.
- (In fact, they can be any distributions -- e.g., nasty things like the
- Dirac delta "function".)
-
- So - the pulses never change shape; there is no dispersion in this
- equation. Of course, simulating the equation on the computer may
- introduce dispersion if your program isn't well-written.
-
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