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- From: max@west.darkside.com (Erik Max Francis)
- Newsgroups: sci.astro
- Subject: Re: Distance of horizon
- Message-ID: <csLkuB9w165w@west.darkside.com>
- Date: 21 Nov 92 03:48:59 GMT
- References: <lglhj3INNb0c@appserv.Eng.Sun.COM>
- Organization: The Dark Side of the Moon +1 408 245 SPAM
- Lines: 24
-
- fiddler@concertina.Eng.Sun.COM (steve hix) writes:
-
- > Anyone have handy a function for figuring the distance of the
- > horizon from a viewer based on the viewer's height from the
- > surface?
-
- I calculated it a while ago to be
-
- s = r arctan [(h^2 + 2 h r)/r^2]^(1/2).
-
- That's where r is the radius of the Earth = 6.37 x 10^6 m and h is the
- height of the observer above the Earth's surface. Note that s is
- measured along an arc, and is not the direct line-of-sight distance; the
- direct LOS distance t = (h^2 + 2 h r)^(1/2).
-
- > This has to do with amusing my kids a bit during our next
- > science discussion. Dad's got to stay ahead *some* way... :}
-
- Regular science discussions for your children? Good man.
-
- ----------
- Erik Max Francis Omnia quia sunt, lumina sunt. Coming soon: UNIVERSE _ | _
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