"LENS EQUATION, FOCAL LENGTH vs INDEX REFRACTION, RADIUS CURV. A diagram of the Problem is shown below. Surface is represented by 's'. · s · R1 radius at center C1 ray · °s· s ° · R2 radius at center C2 · ° s ° · s ° · V1 vertex of sphere 1 · ° s R1 °s · ° · V2 vertex of sphere 2 o······o·····sV1·······V2s····°··o········o S source point S C2 ° ·s n[l]s C1 P P image point s° ·R2 s S[O] Source distance n[m] s ° ·s S[I] Image distance s |V2-V1|<< S[O] or S[I]. |--------S[O]------|-----------S[I]-------| (c) Copyright PCSCC, Inc., 1993 Sign Convention: S[O] + means its left of vertex V2 focal_length < 0 S[I] + means its right of vertex V1 means R? + means center C is right of V diverging lens. *** Answer(s) to problem *** Variables are set to proper values at entry. Note, value of unknown should be set to 0.0. Enter any 4 of 5 knowns, program calculates missing (=0) one. Focal length = 21.24. (b) Positive FL means ray coverge toward optical axis. ||A bi-concave (R1=-8 cm, R2=12 cm) thin lens is made of hepa-fluor (Ng=1.37) and is immersed in solvent alpha-k-1 (Nm=1.77). (a) What isits focal length? (b) is it converging or diverging? Type comma key to see answer. Type (F2) to return to application file."
