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- mode3
- O11
- text/13 5 0 1 1
- For this course, you don't have
- to learn binary counting - just
- know that this is how the com-
- puter uses combinations of on and
- off to count.
- However, if you want to give
- it a try, name this number:
- ~
- O9
- R50 80 243 87
- L150 81 150 87
- L101 79 101 79
- L102 81 102 86
- L198 79 198 79
- L198 81 198 86
- L219 79 219 79
- L220 80 220 86
- L173 79 173 79
- L173 80 173 86
- L126 79 126 79
- L126 81 126 86
- L75 80 75 80
- L75 80 75 86
-
- O11
- text/5 96 0 1 1
- Here's a hint: Remember that the
- rightmost position, if "on" is
- worth 1. The next position to the
- left is worth twice that, if "on"
- is therefore worth 2, and the next
- one to the left of that is worth 4
- and then the next is 8, and so on.
- Just add the ones that are "on"
- together.
-
-
- ~
- KC 48 79 246 89 387 15
- O10
- text 568 31 0 1 1
- 1
- ~
- text 546 31 0 1 1
- 2
- ~
- text 520 31 0 1 1
- 4
- ~
- text 498 31 0 1 1
- 8
- ~
- text 470 31 0 1 1
- 16
- ~
- text 418 31 0 1 1
- 64
- ~
- text 385 40 1 1 0
- 128
- ~
- text 442 40 1 1 0
- 32
- ~
- O12
- L397 27 397 37
- L425 25 425 25
- L425 25 425 28
- L451 25 451 25
- L451 25 451 38
- L477 26 477 26
- L477 25 477 29
- L499 25 499 25
- L499 25 499 28
- L522 25 522 25
- L523 25 523 28
- L547 24 547 24
- L548 25 548 28
- L569 25 569 25
- L569 25 569 28
-
- O11
- text 341 50 1 1 0
- The bits have these values if
- turned on. So to get the decimal
- value of the byte, add up the
- values of the "on" bits.
-
- ~
- O10
- text 462 96 0 1 1
- 128
- ~
- text 478 105 0 1 1
- +16
- ~
- text 478 114 0 1 1
-
-
- ~
- text 485 114 0 1 1
- +8
- ~
- text 485 123 0 1 1
- +1
- ~
- O11
- L463 133 509 133
- O10
- text 469 134 0 1 1
- = ?
- ~
- O11
- text 400 146 0 1 1
- Answer on next page.
- ~
- mode3
- ~
- KY 424 5 569 15
- KY 80 76 222 79
- O0
- P547 24
- P522 25
- O13
- R51 81 73 86
- R127 81 148 86
- R152 81 172 86
- R221 81 241 86
- F67 83 1
- F137 83 1
- F167 83 1
- F235 84 1
- KC 48 79 246 89 387 15
- mode3
-