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- Path: sparky!uunet!dziuxsolim.rutgers.edu!ruhets.rutgers.edu!bweiner
- From: bweiner@ruhets.rutgers.edu (Benjamin Weiner)
- Newsgroups: sci.physics
- Subject: Re: Home made monopoles
- Message-ID: <Jan.27.19.33.33.1993.9143@ruhets.rutgers.edu>
- Date: 28 Jan 93 00:33:34 GMT
- References: <1jr3uiINNcjk@mirror.digex.com> <1993Jan25.171223.5051@novell.com> <1k1nsbINNhte@gap.caltech.edu>
- Organization: Rutgers Univ., New Brunswick, N.J.
- Lines: 36
-
- brahm@cco.caltech.edu (David E. Brahm) writes:
-
- >bdoa@digex.digex.com (Barry Adams) wrote,
- >> Home made magnetic monopoles
- >> [Glue together 2 hemispheres each magnetized with "North" at its pole]
-
- Actually I think Adams meant hemispheres magnetized radially outward,
- so that for each one, the field lines point out of the hemispherical
- surface and in through the flat part.
-
- >dseeman@novell.com (Daniel Seeman) writes:
- >> ...Just because we "know" the South Pole exists in the volume cavity
- >> inside doesn't mean we can actually "see" it...
-
- >I don't know who's serious and who's joking here, but for the record,
- >Adams's construction is not a monopole (I believe it's a quadrupole).
- >Field lines outside the sphere emerge from each pole and re-enter at the
- >equator; "glue" doesn't stop them! You can't make something that violates
- >Gauss's Law of Magnetism (del.B=0) by superposing things that obey it.
-
- This last statement is quite correct and applies to the radially-magnetized
- version as well. I might as well blow the punchline, maybe some people will
- benefit. Consider Gauss's law of magnetism: usually one writes this as
- div B = 0.
- This is true at any point; hence no point can have net outflow/inflow
- of magnetic field lines. But it's also true of surfaces; remember the
- integral form of Gauss's law of magnetism.
- integral(B dot dS) = 0,
- where the integral is over a closed surface and dS is a surface element, and
- "0" = zero is the enclosed magnetic charge. (Inspired by my high-school
- calc class using "plus an arbitrary constant, zero" for indefinite integrals.)
-
- Take this integral over a sphere just at the surface of the magnetized
- sphere, and you see that if B is everywhere outward then the integral
- cannot be zero, so no dice. In fact given that the arrangement maintains
- spherical symmetry the B-field will vanish everywhere, by symmetry
- arguments.
-