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- From: wbdst+@pitt.edu (William B Dwinnell)
- Newsgroups: sci.math.stat
- Subject: Re: Desperate situation
- Message-ID: <2618@blue.cis.pitt.edu>
- Date: 27 Jan 93 14:05:06 GMT
- References: <2581@blue.cis.pitt.edu> <00967347.5659DB00@uinpla.npl.uiuc.edu> <1k5246INN2d4@SALMON.ZOO2.CS.YALE.EDU>
- Sender: news+@pitt.edu
- Organization: University of Pittsburgh
- Lines: 13
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-
- While I'll readily accept the definition (interpretation) of "average",
- as you guys are using it, with respect to this problem, it should
- be noted that means are not just "means". By this I mean that a mean
- is just taking over a series of numbers, but rather it s
- is of a series of numbers, over some domain. Remember, when you
- calulate them mean, you e perform a summation, and divide by some value
- (typically the highest value in the domain). So, you have calculated
- the mean number of attempts, over people who try, whereas I
- calculated the number of tries, when half of the people would be
- dead (the median). Actually, my number is a mean, but in a different
- domain. My number was the mean un number of attempts made, over
- possible outcomes (I think).
-