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- Path: sparky!uunet!opl.com!hri.com!ukma!cs.widener.edu!dsinc!pitt.edu!wbdst
- From: wbdst+@pitt.edu (William B Dwinnell)
- Newsgroups: sci.math.stat
- Subject: Re: Desperate situation
- Message-ID: <2567@blue.cis.pitt.edu>
- Date: 26 Jan 93 19:43:43 GMT
- References: <1993Jan26.183234.20186@mksol.dseg.ti.com> <2564@blue.cis.pitt.edu>
- Sender: news+@pitt.edu
- Organization: University of Pittsburgh
- Lines: 14
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- Assuming that you mean by the "average" person, the point at which half
- of the people have diesxxx (sorry, I did it again!) diesxsasdc
- died, the following progression applies:
- Turn number Cumulative proportion of people dead
- 1 .1667
- 2 .3056
- 3 .4213
- 4 .5177 <-- Oops! Half of 'em are dead! Yuck!
- There may be a way to get an exact figure, like 3.9something something,
- but it escapes me at the moment...
- Any more questions?
- By the way a Monte Carlo simulation, or a Las Vegas simulation might
- help here...
-