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- Path: sparky!uunet!olivea!sgigate!rutgers!igor.rutgers.edu!pepper.rutgers.edu!gore
- From: gore@pepper.rutgers.edu (Bittu)
- Newsgroups: sci.math
- Subject: Combinatorial? problem
- Keywords: binomial coefficients
- Message-ID: <Jan.25.13.57.36.1993.8117@pepper.rutgers.edu>
- Date: 25 Jan 93 18:57:37 GMT
- Organization: Recreation Center, Busch Campus
- Lines: 16
-
-
- A few weeks ago I posted the following problem:
-
- (2m)! (2n)!
- Prove that ------------- is an integer where m,n are integers >=0
- m! n! (m+n)!
-
- I wanted a combinatorial proof. I still haven't found one (in fact I
- believe this is *open*) but I found a very simple proof by induction.
-
- Let F(m,n) denote the above quantity. It is clear that F(m,0) is an
- integer for all m >= 0. Now we only need to observe that
-
- F(m,n) = 4F(m,n-1) - F(m+1,n-1) to complete the proof.
-
- --Bittu
-