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- From: nevin@apple.com (Nevin ":-]" Liber)
- Subject: Re: RAAARRGGHH!!!!! not again! (was:Re: Are you sure?)
- Sender: news@gallant.apple.com
- Message-ID: <nevin-270193200143@nevin.apple.com>
- Date: Thu, 28 Jan 1993 04:07:07 GMT
- References: <1993Jan22.131719.36@janus.arc.ab.ca> <1993Jan25.115908.41@janus.arc.ab.ca> <1993Jan26.095218.17387@cbfsb.cb.att.com>
- Organization: Apple Computer, Inc.
- Followup-To: rec.puzzles
- Lines: 22
-
- In article <1993Jan26.095218.17387@cbfsb.cb.att.com>,
- cooper@cbnewsg.cb.att.com (Ralph 'Hairy' Moonen) wrote:
- >Try this analogy, and you'll see
- > what's wrong with your answer.
- >
- > You are throwing 2 consecutive dice. The first one turns up a six. What is
- > the chance of the second also being a six. It's easy to see that because dice
- > have no memory, the chance is also 1/6. Now, following your line of reasoning,
- > there are 36 different ways to throw the dice. Because 1 six already has
- > been thrown this leaves 11 combinations, one of which is a double six.
- > So, according to you, you only have 1/11 chance of throwing a second six.
- > Clearly this is dead wrong.
-
- Yes, your analogy is dead wrong. The analogy for the original problem is:
-
- You are throwing two dice, and at least one of them turns up a six. What
- are the chances that you rolled a total of twelve? If you believe that the
- answer is 1/6 and not 1/11, please come over and bet me anytime. :-)
- NEVIN ":-)" LIBER, RISC Meanie, Mac System Software
- email: nevin@apple.com paper: Apple Computer, Inc.
- voice: (408) 974-MIX1 20525 Mariani Avenue, MS: 81-GC
- AppleLink: BADENOV Cupertino, CA 95014
-