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- Newsgroups: rec.puzzles
- Path: sparky!uunet!mdisea!uw-coco!uw-beaver!cornell!karr
- From: karr@cs.cornell.edu (David Karr)
- Subject: Re: sphere packing
- Message-ID: <1993Jan28.192514.14094@cs.cornell.edu>
- Organization: Cornell Univ. CS Dept, Ithaca NY 14853
- References: <1993Jan26.235433.18005@cs.ucla.edu>
- Date: Thu, 28 Jan 1993 19:25:14 GMT
- Lines: 26
-
- In article <1993Jan26.235433.18005@cs.ucla.edu> byron elbows writes:
- >I need help on a sphere packing question. Suppose you have a white ping
- >pong ball, and 13 red ones, all the same size. Can you glue all of the red
- >ping pong balls to the white one? [...]
- >
- >It is a simple matter to do it with 12. Simply place the spheres at the
- >corners of an icosahedron centered at the center of the white ping pong ball.
- >It turns out this leaves some extra room for spheres to be moved around [...]
-
- This remark caused me to wonder what is the diameter of a sphere
- circumscribed about an icosahedron of side 1. (Presumably it's less
- than 2, so that the above works.) It would be nice if there were a
- simple, painless answer to this, but I couldn't think of anything that
- didn't involve lots of trigonometry. Does anyone know a very simple
- method to compute this?
-
- By the way, you also get 12 spheres around a central one if you use
- either hexagonal or cubic close packing, in which 6 of the spheres lie
- in one plane (along with the center sphere) with centers at the
- vertices of a regular hexagon. In this configuration all the
- surrounding spheres just barely fit in around the central one with no
- "wiggling room," but it's easy enough to verify by diagram that the
- configuration works.
-
- -- David Karr (karr@cs.cornell.edu)
-
-