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- Path: sparky!uunet!elroy.jpl.nasa.gov!nntp-server.caltech.edu!SOL1.GPS.CALTECH.EDU!CARL
- From: carl@SOL1.GPS.CALTECH.EDU (Carl J Lydick)
- Newsgroups: rec.puzzles
- Subject: Re: Are you sure? YES <SPOILER>
- Date: 26 Jan 1993 13:42:09 GMT
- Organization: HST Wide Field/Planetary Camera
- Lines: 60
- Distribution: world
- Message-ID: <1k3f3hINN29k@gap.caltech.edu>
- References: <1993Jan22.131719.36@janus.arc.ab.ca> <1993Jan25.145759.2592@cs.cornell.edu>,<1993Jan26.115545.11556@eng.cam.ac.uk>
- Reply-To: carl@SOL1.GPS.CALTECH.EDU
- NNTP-Posting-Host: sol1.gps.caltech.edu
-
- In article <1993Jan26.115545.11556@eng.cam.ac.uk>, cmh@eng.cam.ac.uk (C.M. Hicks) writes:
- =karr@cs.cornell.edu (David Karr) writes:
- =
- =>>You meet the daughter of a friend of yours on the street. You know
- =>>that your friend has two children. You think to yourself, "Ignoring
- =>>the occurrence of twins, and sex-linked differences in birth rates
- =>>and infant mortality, what are the odds of this girl's sibling also
- =>>being a girl?"
- =
- =One half - The probability of the other child being a girl is totally
- =independent of the sex of the first. The first child being
- =a girl does affect the 50-50 boy-girl distribution of the second (or any
- =other) child.
- =
- =Even if your friend had 10 children, and you met nine of them in the street,
- =all girls, then the probability of the tenth being female is still one half.
- =
- =Of course, the probability of having ten girls is 1/1024 (assuming no
- =genetic oddities), but the probability of any one child being a girl is
- =one half
-
- OK, maybe if we do this by enumeration, it'll convince people. Suppose there
- are four families. One has two boys, one two girls, one has an older boy and
- youger girl, and the fourth has an older girl and younger boy. Are you agreed
- that each of these four possibilities is equally likely? Now, suppose as
- you're walking around, you run into each of these children separately. Are you
- agreed that the odds of meeting them are identical? If so, then we have the
- following equiprobably possibilities:
-
- Description of child you meet Gender of sibling
- -------------------------------- -----------------
- Oldest boy from first family Male
- Youngest boy from first family Male
- Oldest girl from second family Female
- Youngest girl from second family Female
- Boy from third family Female
- Girl from third family Male
- Boy from fourth family Female
- Girl from fourth family Male
-
- Each of these is equally likely. Now we note that the problem speficies that
- you met a girl. The possibilities here are:
-
- Description of child you meet Gender of sibling
- -------------------------------- -----------------
- Oldest girl from second family Female
- Youngest girl from second family Female
- Girl from third family Male
- Girl from fourth family Male
-
- Thus there's a 50% chance that the sibling is female. This is *NOT* the same
- as the "I've got two children and at least one of them is a girl" question.
- --------------------------------------------------------------------------------
- Carl J Lydick | INTERnet: CARL@SOL1.GPS.CALTECH.EDU | NSI/HEPnet: SOL1::CARL
-
- Disclaimer: Hey, I understand VAXen and VMS. That's what I get paid for. My
- understanding of astronomy is purely at the amateur level (or below). So
- unless what I'm saying is directly related to VAX/VMS, don't hold me or my
- organization responsible for it. If it IS related to VAX/VMS, you can try to
- hold me responsible for it, but my organization had nothing to do with it.
-