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- From: cmh@eng.cam.ac.uk (C.M. Hicks)
- Newsgroups: rec.audio
- Subject: Re: A wire with loss
- Message-ID: <1993Jan27.164451.4206@eng.cam.ac.uk>
- Date: 27 Jan 93 16:44:51 GMT
- References: <19930126.050304.116@almaden.ibm.com>
- Sender: cmh@eng.cam.ac.uk (C.M. Hicks)
- Organization: cam.eng
- Lines: 44
- Nntp-Posting-Host: club.eng.cam.ac.uk
-
- BARRON@RHQVM14.VNET.IBM.COM writes:
-
- >Some have refered to an ideal amp as a wire with gain.
-
- >Along with a previous appender, I would like a 'wire with loss'.
-
- >This would go directly between my CD player and my amp for
- >'reference listening'.
-
- >Assume my amp and CD have input/output impedances of 50k.
-
- I thoroughly doubt that the output impedance of your CD player is anywhere
- near 50k - between 100 ohms and 1k0 seems more likely.
-
- >Can I simply use a few 1% resistors and construct a voltage divider?
-
- Yes, you can do this fine - just keep the overall load on the CD above
- about 10k. The easiest way is to use the input impedance of the pre-amp
- as the lower half of the divider by putting a resistor in series with
- the CD player output.
-
- Assuming 50k input impedance, and <1k0 output impedance, the following table
- is approximately correct:
-
- Attenuation Resistance
- ==============================
- 3dB 20k
- 6dB 50k
- 12dB 150k
- 20dB 450k
-
- >Anything else I should know?
-
- Audiophiles who use cables costing $xxx.xx will faint at the suggestion
- that you could possibly put anything as horrible as a resistor in the signal
- path... :-)
-
- Christopher Hicks
-
- --
- ==============================================================================
- Christopher Hicks | If it doesn't fit...
- cmh@uk.ac.cam.eng | ...you need a bigger hammer.
- ==============================================================================
-