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- Path: sparky!uunet!munnari.oz.au!uniwa!uniwa!nfm
- From: rmascaro@uniwa.uwa.edu.au (Robert Mascaro)
- Newsgroups: comp.os.msdos.programmer
- Subject: interupt vector table
- Date: 22 Jan 1993 09:21:28 +0800
- Organization: The University of Western Australia
- Lines: 10
- Message-ID: <1jni6oINNkjt@uniwa.uwa.edu.au>
- NNTP-Posting-Host: uniwa.uwa.edu.au
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-
- I have a strong interest in writing software interupt handlers. I know
- that dos keeps a table of 1024 bytes from 0:0 which point to the address
- to jump to from servicing the interupt. My question is, I have tryed to
- follow the path (using debug) of interupt 1C (second clock timer), which
- by my calculations should be located at hex 0:70 (4 bytes per address *
- int number). This should contain the offset address of the handler which
- should point to an IRET. It seems to point to nothing. What am I doing
- wrong?? could someone step me through the process in DEBUG.
- Thankyou in advance,
- Rob.
-