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- Newsgroups: sci.math.research
- Path: sparky!uunet!think.com!sdd.hp.com!ux1.cso.uiuc.edu!news.cso.uiuc.edu!dan
- From: phillips@bright.uoregon.edu (Chris Phillips)
- Subject: Algebraic topology question
- Message-ID: <9301020127.AA24551@bright.uoregon.edu>
- Originator: dan@symcom.math.uiuc.edu
- Sender: Daniel Grayson <dan@math.uiuc.edu>
- Followup-To: poster
- X-Submissions-To: sci-math-research@uiuc.edu
- Organization: University of Illinois at Urbana
- X-Administrivia-To: sci-math-research-request@uiuc.edu
- Approved: Daniel Grayson <dan@math.uiuc.edu>
- Date: Sat, 2 Jan 1993 01:27:47 GMT
- Lines: 37
-
- Let P_n be the product of n copies of the 2-sphere S^2. In the
- singular cohomology group H^2 (P_n, Z/rZ), let g_1, ..., g_n be the
- generators corresponding to the factors of P_n. I have a topological
- space E, an element x in H^2 (E, Z/rZ), and a continuous map f from
- P_n to E such that f*(x) = g_1 + ... + g_n. Here E is an open subset
- of a compact manifold, and even probably has finitely generated
- cohomology. The object is to get lower bounds on the dimension of the
- manifold that contains E, and which go to infinity when n goes to
- infinity.
-
- A while ago, I did something similar using Z coefficients instead of Z/rZ.
- In this case, f*(x^n) = (g_1 + ... + g_n)^n, which is n! times a generator
- of H^2n (P_n, Z) = Z. So H^2n (E, Z) is not zero. In the present case, r
- is fixed (and presumably much smaller than n), but (g_1 + ... + g_n)^n
- is zero as soon as r divides n!. If r is prime, this means the method only
- works for n<r. In that case, if n=r then a cohomology operation called a
- generalized Pontrjagin power, when applied to g_1 + ... + g_r, yields a
- nonzero element of H^2r (P_r, Z/r^2Z). Therefore H^2r (E, Z/r^2Z) is not
- zero. But even this seems not to be helpful for n>r.
-
- What I am really hoping to find is a cohomology operation which one can
- apply to g_1 + ... + g_n and get a nonzero element of H^2n (P_n, A) for
- some coefficient group A, for n >> r. Of course, it doesn't have to be
- exactly H^2n; anything close would help. Any other ideas would also be
- appreciated. Of course, what I want may be false. If somebody can produce
- for me an open subset U of R^5, say, and a continuous map f from
- S^2 x S^2 x S^2 to U such that the restrictions of f to the sets
- S^2 x point x point, point x S^2 x point, and point x point x S^2 are
- all homotopically nontrivial, then I would probably give up on this
- approach entirely.
-
- Two additional items that might possibly be relevant: E is probably
- simply connected, and H_2 (E, Z) is probably isomorphic to Z/rZ. (So
- the U above should really be simply connected.)
-
- Please reply to phillips@math.uoregon.edu. Thanks.
-
-