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- Newsgroups: sci.math
- Path: sparky!uunet!world!mrob
- From: mrob@world.std.com (Robert P Munafo)
- Subject: Re: Two (I think) interesting Problems
- Message-ID: <BzyGs7.AA@world.std.com>
- Summary: Here's how to make the 1:sqrt(2) rectangle out of any rectangle
- Keywords: paperfolding pentagon origami geometry long
- Organization: The World Public Access UNIX, Brookline, MA
- References: <1992Dec23.134651.7759@neptune.inf.ethz.ch> <1992Dec28.013845.23064@infodev.cam.ac.uk> <1992Dec28.031441.17199@news.media.mit.edu>
- Date: Mon, 28 Dec 1992 06:02:31 GMT
- Lines: 38
-
-
- > Fascinating. We unhappy americans have no convenient source of
- > root(2) paper.
-
- Well, of course we could use a paperfolding method to generate a 1:sqrt(2)
- from an arbitrary rectangle:
- - Fold a short edge of the rectangle so that it meets a long edge,
- forming a five-sided shape with a 45-degree angle at one end of the
- fold you have just created. Call the point with the 45-degree corner
- "Point A". Then, open it flat again.
- - One of the long edges of the rectangle has Point A as one of its
- endpoints. Call the other endpoint of this edge "Point B". Fold this
- edge so that it coincides with the crease you
- made in the first step, forming a 67.5-degree angle at Point A. If
- the rectangle you started with is more square than 1:sqrt(2) (e.g.
- 8.5x11 US Letter paper) you will now have a pentagonal shape; continue
- with the next step. Otherwise (e.g. 8.5x11 US Legal paper) you have a
- non-convex polygon of some kind; skip down to step "*".
- - (Still in the pentagonal shape) fold again so that Point A coincides
- with Point B.
- - Part of the short edge of the original rectangle is now parallel to
- the unfolded long edge. Fold this long edge forming a crease that
- coincides with the parallel short edge, extending the crease all the
- way past the folded-in corners.
- - Unfold the two previous folds, leaving only this last fold. You now
- have a 1:sqrt(2) rectangle.
- * (For rectangles that were less square than 1:sqrt(2)): The long edges
- of the original rectangle cross; call this point "Point C". Make a
- new fold so that one endpoint of the new crease is at Point C, and
- so that Point B lands on the edge AB.
- - Unfold both. Part of the second crease you made will be parallel to
- the short edge of the rectangle. Fold along this crease, extending
- the crease all the way to the other long edge. The distance from
- this crease to the short edge containing Point A is sqrt(2) times the
- length of the short edge. If your original was longer than 0.5:sqrt(2),
- you'll have to fold more times to get rid of the excess.
-
- - Robert P. Munafo (yup, the computer ate my .signature)
-