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- From: dwr2560@zeus.tamu.edu (RING, DAVID WAYNE)
- Newsgroups: rec.puzzles
- Subject: Re: Direction of the sun
- Date: 25 Dec 1992 15:37 CST
- Organization: Texas A&M University, Academic Computing Services
- Lines: 46
- Distribution: world
- Message-ID: <25DEC199215373265@zeus.tamu.edu>
- References: <1992Dec24.012636.17115@Csli.Stanford.EDU> <Bzr9GF.3uM@hplabs.hpl.hp.com>
- NNTP-Posting-Host: zeus.tamu.edu
- News-Software: VAX/VMS VNEWS 1.41
-
- potamian@hpl.hp.com (Spyros Potamianos) writes...
- >>A points to the sun and says:
- >>"This is the direction where the sun is right now."
- >>B replies:
- >>"But don't you know that the rays take over 8 minutes to reach the Earth?
- >>The sun is actually already below the horizon."
- >>Which is correct? Why? (Make it understandable to a ten year-old.)
- >># note: ignore subsidiary points like refraction by the atmosphere.
-
- Also ignoring the motion of the earth around the sun which displaces
- the sun's direction slightly in the opposite direction (I think).
-
- >Now, let's go to a "solarcentric" system.
- >The sun is still, positioned again at (d,0) and the earth is at (0,0)
- >rotating counterclockwise (around itself, *not* around the sun!)
- >with an angular velocity 'w'.
- >An observer standing on the earth (assume a zero earth radius, after all
- >it's very small compared with 'd') uses a different system of coordinates
- >X'Y'.
-
- >As you can see, its velocity has a non zero Y component. The photon will
- >appear to be coming from an angle:
- > a = arctan( v'y/v'x ) = arctan (sin(w*d/c)/cos(w*d/c))
- > = arctan(tan(w*d/c))
- > = w*d/c
- >
- >I.e. the sun will appear being at an angle 'w*d/c' "above" its current
- >position, a result consistent with the one we got from the "solarcentric"
- >system (BTW, this angle is around 2 degrees)
-
- The sun actually _is_ at an angle w*d/c above the direction which you
- are calling 'its current position'. I.e. it is not stationary in the
- X'Y' coordinates.
-
- Dave Ring
- dwr2560@zeus.tamu.edu
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