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- Path: sparky!uunet!spool.mu.edu!olivea!charnel!sifon!thunder.mcrcim.mcgill.edu!mouse
- From: mouse@thunder.mcrcim.mcgill.edu (der Mouse)
- Newsgroups: rec.puzzles
- Subject: Re: Paper Folding
- Message-ID: <1992Dec23.055335.19381@thunder.mcrcim.mcgill.edu>
- Date: 23 Dec 92 05:53:35 GMT
- References: <1992Dec15.071749.20479@serval.net.wsu.edu> <1992Dec17.134838.29102@serval.net.wsu.edu>
- Organization: McGill Research Centre for Intelligent Machines
- Lines: 47
-
- In article <1992Dec17.134838.29102@serval.net.wsu.edu>, wvanweer@wsuaix.csc.wsu.edu (Wayne VanWeerthuizen) writes:
- > In article <1992Dec17.120841.14563@thunder.mcrcim.mcgill.edu> mouse@thunder.mcrcim.mcgill.edu (der Mouse) writes:
-
- >> Does the paper have stripes on both sides? Do the stripes run the
- >> same way on both sides?
- > Okay, the stripes run on only ONE side of the paper. The paper can
- > start out with any shaped perimeter, but must be flat and one
- > continuous piece.
-
- Must it be simply connected? Is it allowed to have cuts that do not
- remove material?
-
- If it is allowed to have cuts that remove no material, I have a
- solution in nine unit squares; this can be reduced to six plus epsilon
- by trimming three of the squares down to narrow rectangles.
-
- > Oh, and two more provisions. If the paper is laid back flat after
- > having been folded, all the small sections delimited by the creases,
- > must be convex, with no holes. And for two regions to be connected
- > they must share at least a line segment at the crease of length 1/2.
-
- Then the three squares can't be trimmed below area 1/2, and my least
- area is 7.5 units. This can be reached as follows:
-
- Given the positive quadrant divided into unit squares, take the squares
- with their lower left corners at the following points:
-
- (0,0) (0,1) (0,2)
- (1,1) (1,2) (1,3)
- (2,2) (2,3) (2,4)
-
- Cut along the line segments (1,1)-(1,2) and (2,2)-(2,3).
-
- Cut out and remove the right-hand half (ie, the rectangle with x values
- whose fractional parts are between .5 and 1) of the (0,1), (1,2), and
- (2,3) squares. Crease all the remaining connections the same way (all
- mountain or all valley folds). It should be trivial to fold it into a
- cube at this point; if you fold it so that all the partial squares are
- hidden, the result should be the answer. (Assuming, of course, that
- the folds are mountain folds for the side with lines on it.)
-
- I hope I got all those coordinates right... :-)
-
- der Mouse
-
- mouse@larry.mcrcim.mcgill.edu
-