home *** CD-ROM | disk | FTP | other *** search
- Newsgroups: rec.bicycles.tech
- Path: sparky!uunet!zaphod.mps.ohio-state.edu!sdd.hp.com!ux1.cso.uiuc.edu!news.cso.uiuc.edu!vmd.cso.uiuc.edu!EPLUS17
- From: EPLUS17@vmd.cso.uiuc.edu (Richard Engelbrecht-Wiggans)
- Subject: Re: Phil Wood hubs
- References: <1992Dec29.055254.14564@news.ysu.edu>
- Message-ID: <168CC1117B.EPLUS17@vmd.cso.uiuc.edu>
- Sender: usenet@news.cso.uiuc.edu (Net Noise owner)
- Organization: C.C.S.O.
- Date: Wed, 30 Dec 1992 01:26:45 GMT
- Lines: 40
-
- In article <1992Dec29.055254.14564@news.ysu.edu>
- ae505@yfn.ysu.edu (Frank Krygowski) writes:
-
- >
- >For a hollow one, it's more complicated, 'cause you get to play
- >around with both the inside and outside diameters. The similar
- >formula would be:
- >
- > Sy * pi * (Do^4 - Di^4)
- > FS = ----------------------------
- > 32 * M * Do
- >
- >where Do & Di are outside and inside diameters. It's not a straight
- >proportion, because of that difference in diameters to the fourth
- >power, but the general idea is the same. Strength is roughly
- >proportional to the cube of the diameter. Of course, weight
- ::::
- >goes up unless you make the walls thinner.
- >
-
- Let me factor that equation as follows:
-
- Sy * pi * ((Do:2+(Do-(Do-Di)):2) * (Do+(Do-(Do-Di)) * (Do-Di)
- FS = ------------------------------------------------------------
- 32 * M * Do
-
- Now, if the wall thickness Do-Di is mallish compared to the outside
- diameter, then the first order approximation becomes
-
- Sy * pi * 2Do:2 * 2Do + (Do-Di)
- FS = --------------------------------------------
- 32 * M * Do
-
- Cancel a Do top and bottom, and you see that for fixed wall thickness,
- the strength of tubing goes very nearly as the SQUARE as the diameter,
- as I claimed earlier, not as the cube of the diameter.
-
- ..Richard E+17
-
-
-