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- Newsgroups: comp.graphics
- Path: sparky!uunet!cs.utexas.edu!uwm.edu!daffy!uwvax!skyler.cs.wisc.edu!seitz
- From: seitz@skyler.cs.wisc.edu (Steve Seitz)
- Subject: Re: How many dots in a circle?
- Message-ID: <1992Dec22.231623.22529@cs.wisc.edu>
- Sender: news@cs.wisc.edu (The News)
- Reply-To: seitz@skyler.cs.wisc.edu (Steve Seitz)
- Organization: University of Wisconsin-Madison, Department of Computer Sciences
- References: <1992Dec22.134450.15558@cactus.org> <22DEC199210514406@reg.triumf.ca>
- Date: Tue, 22 Dec 1992 23:16:23 GMT
- Lines: 31
-
- In article <22DEC199210514406@reg.triumf.ca>, noel@reg.triumf.ca (NOEL GIFFIN) writes:
- |>
- |> In article <1992Dec22.134450.15558@cactus.org>, rdd@cactus.org (Robert Dorsett) writes...
- |> Stuff deleted...
- |>
- |> >
- |> >What is the minimum number of discrete points that will exist in the
- |> >perimeter of that circle? And, of more interest, if one has a minimum
- |> >number of points required, what will be the minimum radius needed to
- |> >produce that number?
- |> >
- |> Isn't this just as simple as c = pi * d
- |>
- |> If your short axis display minimum resolution is 600 pixels then the
- |> maximum diameter of a circle to be contained in it is also 600 pixels.
- |> Then the number of pixels in the circumference should be (pi * 600) pixels and
- |> the minumum radius would be of course 400 pixels.
- |>
- |>
- |> Noel@reg.triumf.ca
- |>
-
- I don't believe this will work. Try it for the simple case of a circle of
- radius one. PI * d is about 6. Try drawing a circle with 6 pixels!
- The number of pixels will surely depend on your drawing algorithm. For the
- case of radius 1, the raster circle could equally well have either 4 or 8
- pixels, depending on which algorithm is used.
-
- -Steve Seitz
- Dept. of Computer Sciences
- University of Wisconsin -- Madison
-