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- From: fnord@panix.com (Cliff Heller)
- Newsgroups: alt.folklore.science
- Subject: Re: Monty Hall/Shell Game..
- Message-ID: <1992Dec24.153315.9357@panix.com>
- Date: 24 Dec 92 15:33:15 GMT
- References: <X382VB1w164w@perseus.spk.wa.us> <1992Dec20.180350.7276@panix.com> <BzqJx8.3Fv@unx.sas.com>
- Organization: Right Bleedin' Church of Libertine Obfuscatology
- Lines: 65
-
- In <BzqJx8.3Fv@unx.sas.com> sasjec@asimov.unx.sas.com (Jerry M. Cox) writes:
-
- >Odds are that I could stand a review course in probability. But hear me
- >out anyway :-) If the contestant selects one door of three and that was
- >all there was to it then the odds of initially selecting the winning door
- >are one out of three. I have no problem with that, but I don't think
- >this describes the situation. If Monty is *always* going to reveal a
- >goat behind one of the doors, that door is removed from consideration.
-
- It is precisely because Monty ALWAYS reveals a losing door that makes it
- significant.
-
- All you have to see is that if the initial guess was incorrect, the person
- will always win when they switch. Think about that very carefully. The
- initial guess is incorrect - of the two door, one has the prize, and the
- other has the goat - Monty will reveal the goat, so the door switched to
- will win. This is only in the case when the initial guess was a goat.
-
-
- Now, the probability that the initial guess was incorrect is 2/3. That
- cannot change, because a selection was made from 3 doors, only one of which
- is correct. Monty doesn't remove the door from consideration, because it
- was there when the selection was made.
-
- Sure if he took away one of the doors, and scrambled the prizes and then
- let you select randomly from the two, it would be 50/50, but the guess was
- made from three doors. Revealing a door does not change the probability
- of the original guess, it can't. It does reveal a lot of information about
- the remaining door.
-
- >The final choice then becomes a choice between one of two doors. If
- >Monty *always* removes one of the doors from consideration, then the
- >final choice (as well as the initial choice) is between a door with a
- >car behind it, and a door with the "other" (the one Monty doesn't show)
- >goat behind it. The odds of picking the car are 50/50 whether you switch
- >or not because Monty is *always* going to take away one of the losing
- >choices.
-
- Just because it is a choice between two doors does not make it 50/50
- probability.
-
- >If he said "You can have the door you picked or the TWO doors that you
- >didn't pick", and didn't reveal anything about the two doors, then I
- >would agree that the best thing to do would be to switch.
-
- Ah, but he does equivalently say this. Look at the cases very carefully.
- Any time the prize is in one of the two doors you did not pick, you win,
- and any time the prize is the one that you initially chose, you lose.
-
-
- But, Monty
- >changes the odds when he shows you one of the goats behind one of the
- >two doors. He removes that door from consideration completely.
-
- No one, not even Monty can change the probability of something that you
- already selected from three choices. That remains fixed at 1/3. It cannot
- change.
-
-
-
- --
- / \ Reverend fnord | "King Kong died for your sins!"
- / \ fnord@panix.com |
- / <0> \ | "Don't just eat a hamburger,
- /_______\ Church of Obfuscatology, Inc. | eat the HELL out of it!"
-