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- Xref: sparky sci.physics:19368 alt.sci.physics.new-theories:2376 sci.optics:1187
- Newsgroups: sci.physics,alt.sci.physics.new-theories,sci.optics
- Path: sparky!uunet!well!sarfatti
- From: sarfatti@well.sf.ca.us (Jack Sarfatti)
- Subject: parallel slit kets OK after all?
- Message-ID: <By35BM.LpA@well.sf.ca.us>
- Sender: news@well.sf.ca.us
- Organization: Whole Earth 'Lectronic Link
- Date: Sat, 21 Nov 1992 21:35:46 GMT
- Lines: 114
-
-
- Sarfatti Lectures in Super Physics (Lecture 2)
-
- #7 Quantum connection communication is required if the Princeton PEAR
- reports of "precognitive remote viewing" are a real phenomenon. Quantum
- connection communication may also be required to explain how the universe
- comes into being and what our destiny and ultimate purpose may be. Quantum
- connection communication may be the source of meaning to existence.
-
- Whoops! It appears that one can get a sensible interpretation of the 2 slit
- experiment with parallel slit kets after all!
-
- OK Must the slit kets must be orthogonal? Is there is no sensible way that
- they can be parallel? Let's re-examine the 2-slit experiment and the Mach-
- Zehnder interferometer using standard approach of orthogonal kets and then
- the non-standard approach of parallel slit kets. The latter is sufficient
- to get a quantum connection signal easily. The former, makes it more
- difficult to get the quantum connection signal but still not impossible,
- especially if we monitor detectable hidden orders in the receiver
- fluctuations that may depend on parameters controlled by settings of
- transmitter devices.
-
-
- | | |
- | |1> |
- |i> | |x>|
- | |2> |
- | | |
- slits screen
-
- Fig.7a 2-slit experiment
-
- In Schrodinger picture where kets evolve in time (time evolution notation
- suppressed for simplicity):
-
- |i> = |1><1|i> + |2><2|i>
-
- 1 = |1><1| + |2><2|
-
- <1|2> = 0
-
- <x|i> = <x|1><1|i> + <x|2><2|i>
-
- The probability density at the screen is
-
- p(x) = |<x|i>|^2 = <i|x><x|i>
-
- = <i|1><1|x><x|1><1|i> + <i|2><2|x><x|2><2|i>
-
- + <i|1><1|x><x|2><2|i> + <i|2><2|x><x|1><2|1>
-
- But Integral{|x><x|dx} = 1
-
- Therefore,
-
- Integral{p(x)dx} = <i|[|1><1|+|2><2|]|i>+<i|1><1|2><2|i>+<i|2><2|1><2|1>
-
- = <i|i> = 1
-
- Note that <1|2> = 0 (i.e. orthogonality of the slit kets is necessary to
- get a vanishing integral of the interference terms over the entire screen.
-
- On the other hand, suppose that the slit kets were not orthogonal but
- parallel, so that
-
- |1> = e^i@|2>
-
- <1| = <2|e^-i@
-
- assume phase @ is a c-number not an operator (if we do second-quantization
- it becomes an operator which might change things?)
-
- Therefore,
-
- 1 = |1><1| + |2><2| = 2|1><1|
-
- <1|2> = e^-i@
-
- Therefore,
-
- Integral{p(x)dx} = 2<i|1><1|i>+<i|1>e^-i@<2|i>+<i|2>e^i@<2|1> = 1
-
- Let us simplify to the case of equal illumination so that
-
- <i|1> = <i|2> = 1/sqrt2
-
- with zero phases. Therefore, the condition is simply @ = pi/2 or
-
- |1> = i|2>
-
- In general, the relative phase between the parallel slit kets will be
- dependent on the initial conditions of the input state (i.e., the two
- complex variables <i|1> and <i|2>).
-
- note that for our simple special case
-
- p(x) = |<1|x>|^2[1 + cos@]
-
- which is not at all unreasonable!
-
- Thus, it appears, that assuming parallel slit kets for the 2-slit
- experiment gives a sensible answer. Note that @ = @(x) so that we require
-
- Integral{|<1|x>|^2[1 + cos@(x)]dx} = 1
-
- more specifically since the fringes rearrange a fixed total energy
-
- Integral{|<1|x>|^2dx} = 1
-
- Integral{|<1|x>|^2 cos@(x)dx} = 0
-
- to be continued
-
-
-