home *** CD-ROM | disk | FTP | other *** search
- Newsgroups: sci.physics
- Path: sparky!uunet!well!sarfatti
- From: sarfatti@well.sf.ca.us (Jack Sarfatti)
- Subject: re:Texas A&M inquiry on FTL controversy.
- Message-ID: <Bxvn17.F2C@well.sf.ca.us>
- Sender: news@well.sf.ca.us
- Organization: Whole Earth 'Lectronic Link
- Date: Tue, 17 Nov 1992 20:17:31 GMT
- Lines: 98
-
-
- From WMA6617@VENUS.TAMU.EDU Tue Nov 17 10:20:58 1992
- Date: Tue, 17 Nov 1992 12:21:15 -0600 (CST)
- From: WMA6617@ZEUS.TAMU.EDU
- Subject: Re: Ramsay's claim of Sarfatti contradiction 1=0.
- To: sarfatti@well.sf.ca.us
- X-Vmsmail-To: SMTP%"sarfatti@well.sf.ca.us"
-
- In article <Bxp4I5.Bxy@well.sf.ca.us>, you write...
- Dear sir,
- I have jumped into this conversation in the middle. Could you post or
- E-mail a summary or a FAQ list which whould bring us late comers up to
- date on this discussion.
- Many Thanks
- Bill Ashe
- Stored Ion Lab
- Texas A&M University
-
- Sarfatti replies:
-
- Basic idea, pair source,transmitter,receiver.
- transmitter is calcite with half-wave plate in one path (o) and phase plate
- (phi) in other path (e). Both paths brought together to one counter to make
- an interferometer. Receiver is calcite ant angle theta to transmitter
- calcite with two counters detecting o' and e' paths.
-
- Pair source creates 2-photon entangled state
-
- |a,b> = [|a,e,+>|b,e,+> + |a,o,->|b,o,->}/sqrt2
-
- where, for example, |a,o,-> means photon a in o path with linear
- polarization normally corresponding to that path. However, a half-wave
- plate will cause |a,o,-> -> |a,o,+> which is photon a still on o path but
- with polarization rotated 90 degrees from its normal value. Since the e and
- o paths are going to be recombined erasing the space distinction, and since
- the half-wave plate erases the polarization distinction, I say that |a,e,+>
- and |a,o,+> are "parallel" differing only by a phase factor. That is,
-
- <a,e,+|a,o,+> = |<a,e,+|a,o,+>|e^iarg<a,e,+|a,o,+>
-
- |<a,e,+|a,o,+>| = 1
-
- In contrast,
- <a,e,+|a,o,-> = 0. However, Ramsay claims <a,e,+|a,o,+> = 0 as well.
-
- Therefore, the distorted "disentangled" pair state is:
-
- |a,b>' = [e^iphi|a,e,+>|b,e,+> + |a,o,+>|b,o,->}/sqrt2
-
- = [e^iphi|a,e,+>|b,e,+> + |a,e,+><a,e,+|a,o,+>|b,o,->}/sqrt2
-
- = [e^iphi|a,e,+>|b,e,+> + |a,e,+>e^iarg<a,e,+|a,o,+>|b,o,->}/sqrt2
-
- = |a,e,+>[e^iphi|b,e,+> + e^iarg<a,e,+|a,o,+>|b,o,->}/sqrt2
-
-
- note that <a,b,|a,b> = 1 and '<a,b|a,b>' = 1 also.
-
- Photons a and b in |a,b>' each have their own local pure states of zero
- entropy which is not true for initial state |a,b>.
-
- That is,
-
- |a,b>' = |a>'|b>'
-
- |a>' = |a,e,+>
-
- |b'> = [e^iphi|b,e,+> + e^iarg<a,e,+|a,o,+>|b,o,->}/sqrt2
-
- The local receiver detection probabilities are
-
- p(b,e') = |<b,e',+'|b>'|^2 = [1 + sin(2theta)cos(phi - arg<a,e,+|a,o,+>]/2
-
-
- p(b,o') = |<b,o',-'|b>'|^2 = [1 - sin(2theta)cos(phi - arg<a,e,+|a,o,+>]/2
-
- Therefore, the quantum connection signal is
-
- p(b,e') - p(b,o') = sin(2theta)cos(phi - arg<a,e,+|a,o,+>)
-
- The transmitter detection probability is
-
- p(a) = |<a,e,+|a,e,+>|^2 = 1
-
- some red herrings:
- 1) the transformation |a,b> -> |a,b>' is not unitary - it obviously is.
- 2) local unitarity for arbitrary one-photon superpositions require that
- cos(phi - arg<a,e,+|a,o,+> = 0. That's comparing apples to oranges - one
- cannot take a reult in one photon Fock space with zero connection and
- assume blindly that it is true in two-photon Fock space with non-zero
- connection because the two situations have different total experimental
- arrangements and must be analyzed separately (i.e., Bohr's principle).
-
-
-
-
-
-
-