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- From: aaronm@cybernet.cse.fau.edu (aaron meyerowitz)
- Subject: Finite axioms of choice
- Message-ID: <sPiguB1w165w@cybernet.cse.fau.edu>
- Originator: dan@symcom.math.uiuc.edu
- Sender: Daniel Grayson <dan@math.uiuc.edu>
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- Approved: Daniel Grayson <dan@math.uiuc.edu>
- Date: Wed, 18 Nov 1992 22:52:15 GMT
- Lines: 19
-
- I've heard this result but can't recall where. Can anyone provide a
- reference or related results for other number pairs?
-
- Theorem: Suppose that there is a choice function for 2 element sets
- , then there is a choice function for 4 element sets.
-
- Proof: Given a set {a,b,c,d} form each of the 6 2-element subsets
- and apply the choice function to it. Each of the four elements is
- chosen 0,1,2 or 3 times. If any is chosen 3 times, choose it (it must
- be unique). If none is chosen 3 times and one is never chosen, choose
- it (IT must be unique. The remaining possibility is that two are chosen
- twice and 2 chosen once. Take the two chosen once (or twice, just decide
- which) and let the chosen element be that chosen by the function for
- that pair/////
-
- So this result might be termed AC2 implies AC4.
- Thanks,
- Aaron Meyerowitz
-
-