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- From: jmount+@CS.CMU.EDU (John Mount)
- Newsgroups: sci.math
- Subject: Re: compactness ?
- Message-ID: <By2vpr.EpJ.2@cs.cmu.edu>
- Date: 21 Nov 92 18:08:14 GMT
- Article-I.D.: cs.By2vpr.EpJ.2
- References: <1992Nov20.211648.3583@research.nj.nec.com>
- Sender: news@cs.cmu.edu (Usenet News System)
- Organization: Carnegie Mellon University
- Lines: 41
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- In article <1992Nov20.211648.3583@research.nj.nec.com>, franz@ccrl.nj.nec.com (test user for max) writes:
- |> I am trying to teach myself analysis; i'm stuck on the notion of compactness.
- |> One book's definition:
- |> A subset S of a metric space E is compact if whenever S is
- |> contained in the union of a collection of open subsets of E,
- |> then S is contained in the union of a finite number of these
- |> open subsets.
-
- You should read the above definition as:
-
- A subset S of a metric space E is compact if for EVERY collection of
- open subsets of E such that the union of the members of E contains S
- there is a finite collection E' contained in E such that S is contained
- the union of the members of E'.
-
- |> The book (M.Rosenlicht,Intro.to Analysis) then gives an example of
- |> a non-compact set- the open interval (0,1), which is contained in the
- |> union of sets (1/n,1) but not contained in any finite number of these.
- |>
- |> ? It seems to me that (0,1) is contained in the collection of
- |> open sets { (0,0.6) (0.5,1) (0,1) } and this has finite subsets that
- |> contain (0,1), so (0,1) should be compact. Does the definition mean that
- |> S must be contained in any possible collection, as opposed
- |> to just one possible collection being sufficient? If so, then
- |> I would intuitively think that a (1/n,..) type construction
- |> would prevent any open set from being compact.
- |> Is a 'collection of sets' a stricter notion than I'm assuming?
- |> (Is 'contained in' the same as 'covered by'?)
-
- The closed interval [0,1] in R with the usual topology is compact. I
- won't prove it here- but you will notice that this fact isn't
- contradicted by the collection E = {(1/n,2),n=1,2....} example because
- while no finite subcollection of E covers [0,1] you will notice that E
- doesn't cover [0,1] either (0 isn't a member of any member of E- so
- fails to be covered).
-
- --
- --- It is kind of strange being in CS theory, given computers really do exist.
- John Mount: jmount+@cs.cmu.edu (412)268-6247
- School of Computer Science, Carnegie Mellon University,
- 5000 Forbes Ave., Pittsburgh PA 15213-3891
-