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- Newsgroups: sci.math
- Path: sparky!uunet!brunix!brunix!dzk
- From: dzk@cs.brown.edu (Danny Keren)
- Subject: Re: compactness ?
- Message-ID: <1992Nov21.013605.22842@cs.brown.edu>
- Sender: news@cs.brown.edu
- Organization: Brown University Department of Computer Science
- References: <1992Nov20.211648.3583@research.nj.nec.com>
- Date: Sat, 21 Nov 1992 01:36:05 GMT
- Lines: 29
-
- franz@ccrl.nj.nec.com (test user for max) writes:
-
- #? It seems to me that (0,1) is contained in the collection of
- #open sets { (0,0.6) (0.5,1) (0,1) } and this has finite subsets that
- #contain (0,1), so (0,1) should be compact. Does the definition mean that
- #S must be contained in any possible collection, as opposed
- #to just one possible collection being sufficient?
-
- Yep - *every* open cover must have a finite sub-cover (by "open cover"
- I mean a collection of open sets that contain the space).
-
- #If so, then
- #I would intuitively think that a (1/n,..) type construction
- #would prevent any open set from being compact.
-
- Not true for any topological space, but true for some classes - for
- instance, in Euclidean space a subset is compact iff it is bounded
- and closed.
-
- #Any insight on understanding the definition (and its relevance)
- #would be appreciated.
-
- Compact spaces have many nice properties. For instance, every
- real valued function on them is bounded (one of the simplest
- properties). That is the reason they were studied so extensively.
-
- -Danny Keren.
-
-
-