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- Newsgroups: sci.math
- Path: sparky!uunet!ornl!rsg1.er.usgs.gov!darwin.sura.net!udel!sbcs.sunysb.edu!hanche
- From: hanche@ams.sunysb.edu (Harald Hanche-Olsen)
- Subject: Re: Geometrical parking problem.
- In-Reply-To: mueller@schaefer.math.wisc.edu's message of 18 Nov 92 14: 31:31 GMT
- Message-ID: <HANCHE.92Nov18193828@ptolemy.ams.sunysb.edu>
- Sender: usenet@sbcs.sunysb.edu (Usenet poster)
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- Organization: University at Stony Brook, NY
- References: <1992Nov17.225821.6579@augean.eleceng.adelaide.edu.AU>
- <1992Nov18.101107.29182@infodev.cam.ac.uk>
- <1992Nov18.143131.25971@schaefer.math.wisc.edu>
- Date: Thu, 19 Nov 1992 00:38:27 GMT
- Lines: 33
-
- >>>>> On 18 Nov 92 14:31:31 GMT, mueller@schaefer.math.wisc.edu (Carl Douglas Mueller) said:
-
- Carl> In article <1992Nov18.101107.29182@infodev.cam.ac.uk> rgep@emu.pmms.cam.ac.uk (Richard Pinch) writes:
- >In article <1992Nov17.225821.6579@augean.eleceng.adelaide.edu.AU>
- >dabbott@augean.eleceng.adelaide.edu.AU (Derek Abbott) writes:
- >>
- >>A car of length L reverses into a parking space without touching the kerb.
- >>Has anyone calculated the minimum theoretical length of the parking space?
- >
- >Yes, it's the length of the car. The commutator of two rotations is
- >a translation, so you can drive sideways by making very small moves of
- >the form LRLR.
- Carl>
- Carl> Actually, there is no MINIMUM. The length of the car is not
- Carl> quite enough, but the length of the car plus epsilon (for any
- Carl> positive epsilon) is enough.
-
- Essentially correct, though the picture is a little bit more
- complicated: The two vector fields at disposal are one (S) for turning
- the steering wheel and one (D) for driving back and forth. The
- sideways slide is [D,[D,S]] if I remember it right. There is a nice
- (and very amusing) account in, I think, a book by Nelson (in the
- Princeton lecture note series? I have it in my office the other side
- of the Atlantic ocean -- a bit hard to look from here).
-
- I suspect Derek may have had a much simpler situation in mind though:
- Apparently the car is not allowed to drive forward? It should be
- quite easy to solve by going the other way: Start parked by the curb,
- turn the steering wheel as far as it will go, and drive out. Once the
- trajectory of the car is computed, place a car ahead as close as
- possible, and you've got your answer.
-
- - Harald
-