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- From: fernee@newton.physics.uq.oz.au (Mark Fernee)
- Subject: Help! Order dependent complex integration
- Message-ID: <BxuqDw.Iuz@bunyip.cc.uq.oz.au>
- Sender: news@bunyip.cc.uq.oz.au (USENET News System)
- Organization: Physics Dept. The University of Queensland
- Date: Tue, 17 Nov 1992 08:32:20 GMT
- Lines: 51
-
- I have come across a double integral of the following form;
-
-
- / / -iwt -iz(t-tau)
- | | dw dz e e
- | | -----------------
- | | (w+a)(z+b)(w+z+c)
- / /
-
- Both integrals are to be evaluated along the real axis from
- minus infinity to infinity. The terms a,b and c are complex
- constants with Im(a), Im(b) and Im(c) > i0 and Im(a) and Im(b)
- >> Im(c). Also t and tau are real and > 0 with t-tau > 0.
-
- I have attempted to evaluate the integral using Cauchy's
- residue theorem by completing a contour around the poles
- for each successive integral, using the sign of the exponent
- in the numerator to determine around which half of the complex
- plane to close the integral.
-
- The problem is that the solution is dependent on the order of
- integration. I have as yet found no means to justifiably order
- the integration.
-
- The solutions that I get, differ by a sign and are as follows;
-
- w integration followed by z integration:
-
- / iat ib(t-tau) ict i(a-c)tau \
- 2 | e e + e e |
- -4pi | ____________________________________ |
- | (c-a-b) |
- \ /
-
- z integration followed by w integration:
-
-
- / iat ib(t-tau) ict i(a-c)tau \
- 2 | e e - e e |
- -4pi | ____________________________________ |
- | (c-a-b) |
- \ /
-
-
- If you could spot my mistake, or offer a solution, please
- E-mail me.
-
- Thanks,
-
- Mark.
-
-