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- From: efrie@luke.eecs.wsu.edu
- Newsgroups: rec.juggling
- Subject: Re: Dynamics of Juggling
- Summary: cascade and shower height for b balls are 4 X's different
- Message-ID: <1992Nov18.005450.4150@serval.net.wsu.edu>
- Date: 18 Nov 92 00:54:50 GMT
- Article-I.D.: serval.1992Nov18.005450.4150
- Expires: 01/01/93
- References: <DEARDEN.92Nov17115131@pacific.cs.ubc.ca>
- Sender: Eddie Frie <efrie@eecs.wsu.edu>
- Organization: Washington State University!
- Lines: 40
-
- Hello,
- I was asking about throw height for numbers. I
- compared shower height to that of cascade. With the
- assumption (suggested by Jack Boyce a while back)
- that your dwell time is such that you release a ball
- just as one lands in the other hand. I have calculated
- the height for the two patterns.
-
- Height_cascade = ((b-1)/tr)^2 [feet]
- Height_shower = 4*((b-1)/tr)^2 [feet]
-
- where:
- o tr = throw rate [thows per second]
- o b = number of balls being juggled
- o I am assuming g = 32 ft/s/s because strangly enough the
- numbers work better using U.S. Customary Units for this.
- o I am also asuming that the launch and land elevations are
- equivalent.
-
- I find that my maximum controllable throw rate is 3 throws per second,
- based on my 4 foot high 71 (that is doing it standing
- in a 8 foot ceiling room and just squeezing it in = 4 feet)
- so for example:
-
- tr=3 thows per second
- b=5 balls
-
- Height_cascade = ((5-1)/3)^2 [feet] = 1.78 feet (*) ss = 5
- Height_shower = 4*((5-1)/3)^2 [feet]= 7.11 feet ss = 91
-
- So no wonder I can't shower 5 in my appartment :)
- I think this (*) sounds about right because my tightest
- 5 ball cascade is about that high.
- Also, from the above, a 51 is the same height as a 5
- or a 71 a 7.
-
- I guess if ceilings weren't so low there would be
- more numbers jugglers out there :^}.
-
- -Eddie Frie WSU Juggling Club
-