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- From: lupienj@hpwadac.hp.com (John Lupien )
- Date: Mon, 16 Nov 1992 22:24:37 GMT
- Subject: Re: Rotary vs. Piston Engines
- Message-ID: <3926@hpwala.wal.hp.com>
- Path: sparky!uunet!charon.amdahl.com!pacbell.com!sgiblab!sdd.hp.com!hpscit.sc.hp.com!scd.hp.com!hpscdm!hplextra!hpcss01!hpwala!hpwadac!lupienj
- Newsgroups: rec.autos
- References: <184132@pyramid.pyramid.com> <1992Nov12.014944.26797@walter.bellcore.com> <1992Nov12.142908.17223@cbfsb.cb.att.com>
- Sender: netnews@hpwala.wal.hp.com
- Reply-To: lupienj@wal.hp.com (John Lupien )
- Lines: 27
-
- In article <1992Nov12.142908.17223@cbfsb.cb.att.com> jjn@cbjjn.cb.att.com (Jeff Nappi) writes:
- >least of there problems is the engine. I read the biggest task facing
- >the team is the 610lb storage tank they need for the hydrogen fuel, besides
- >being so big it only has about 124 miles fuel capcity before a recharge is
- >needed. I wonder what kind of power this engine would generate?
-
- This is something you could work out pretty easily.
- I don't have the right references handy to give the Final Answer,
- but here's how to go about looking it up:
-
- First, the number of molecules of cumbustibles is the same
- per unit volume of fuel vapor (hydrogen or gasoline).
- Stoichimetric mixture for gasoline is 1:14 fuel vapor to air.
- Stoichimetric mixture for hydrogen is 2:5 H2 to air (based on
- air containing 20% O2, and 2H2 + O2 -> 2H2O).
- Assuming atmospheric charging in both cases, you are burning about 6 times as
- many H2 molecules per charge as you would gasoline. So, if the
- specific energy of combustion of gasoline is more than 6 times the
- specific energy of combustion of hydrogen, you'll get less power with hydrogen,
- otherwise you'll get more power (or the same). Unfortunately I lent my
- book about thermodynamics of engines to Bernhard Meister (if you see this,
- I WANT IT BACK!!!) years ago, so I'll have to look in a more pedestrian
- reference for the specific energies. Maybe tomorrow...
-
- ---
- John R. Lupien
- lupienj@wal.hp.com
-