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- From: hcb@world.std.com (Howard C Berkowitz)
- Subject: Re: Wanted: Advice on calculating timing gaps between packets.
- Message-ID: <Bxw4sp.n22@world.std.com>
- Organization: The World Public Access UNIX, Brookline, MA
- References: <BARNETT.92Nov9112747@grymoire.crd.ge.com>
- Date: Wed, 18 Nov 1992 02:41:13 GMT
- Lines: 26
-
- A few random things to consider. You will never get the true 10 MBPS from
- an IEEE 802.3/ETHERNET LAN, due to some timing requirements of the protocol
- itself. There must be a minimum 9.6 microsecond delay between packets; this
- is part of the medium access control process. There must be enough idle
- time that the most distant station will hear a jam signal.
-
- Assuming a single transmitter and a single receiver, the maximum possible
- frame-level transfer rate will be based on the length (or length distribution)
- of frames, plus the interframe delay.
-
- I often find it worthwhile to write a reasonably quick-and-dirty Monte Carlo
- simulation of the line protocols rather than go too far in analyzing them.
-
- Retransmission time will be based on the time to send the colliding frames, the
- interframe delay, and the time to send the next frame. The backoff algorithm
- uses an exponentially increasing delay after each successive collision. In a
- reasonably loaded network, a frame should get through with a maximum of 3-4
- collisions (this is fairly pessimistic).
-
- So much depends on the interarrival times of new frames, the length of frames, and
- the number of stations that simulation often is easier.
-
-
- Always remember that ETHERNET is a service to Arnold Schwarzenegger. After all, it
- is a cable that connects Terminator I with Terminator II. :-)
-
-