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PC World 2005 December (Special)
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framework-2.5.exe
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groups
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2005-04-14
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#!/bin/sh
# groups -- print the groups a user is in
# Copyright (C) 1991, 1997, 2000, 2002, 2004 Free Software Foundation, Inc.
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2, or (at your option)
# any later version.
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software Foundation,
# Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
# Written by David MacKenzie <djm@gnu.ai.mit.edu>.
# Make sure we get GNU id, if possible; also allow
# it to be somewhere else in PATH if not installed yet.
PATH=/usr/bin:$PATH
usage="Usage: $0 [OPTION]... [USERNAME]...
--help display this help and exit
--version output version information and exit
Same as id -Gn. If no USERNAME, use current process.
Report bugs to <bug-coreutils@gnu.org>."
version='groups (GNU coreutils) 5.3.0
Written by David MacKenzie.
Copyright (C) 2004 Free Software Foundation, Inc.
This is free software; see the source for copying conditions. There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.'
fail=0
case $# in
1 )
case "z${1}" in
z--help )
echo "$usage" || fail=1; exit $fail;;
z--version )
echo "$version" || fail=1; exit $fail;;
* ) ;;
esac
;;
* ) ;;
esac
if [ $# -eq 0 ]; then
id -Gn
fail=$?
else
for name in "$@"; do
groups=`id -Gn -- $name`
status=$?
if test $status = 0; then
echo $name : $groups
else
fail=$status
fi
done
fi
exit $fail