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- /* Allocate memory region filled with spaces.
- Copyright (C) 1991 Free Software Foundation, Inc.
-
- This file is part of the libiberty library.
- Libiberty is free software; you can redistribute it and/or
- modify it under the terms of the GNU Library General Public
- License as published by the Free Software Foundation; either
- version 2 of the License, or (at your option) any later version.
-
- Libiberty is distributed in the hope that it will be useful,
- but WITHOUT ANY WARRANTY; without even the implied warranty of
- MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
- Library General Public License for more details.
-
- You should have received a copy of the GNU Library General Public
- License along with libiberty; see the file COPYING.LIB. If
- not, write to the Free Software Foundation, Inc., 59 Temple Place - Suite 330,
- Boston, MA 02111-1307, USA. */
-
- /*
-
- NAME
-
- spaces -- return a pointer to a buffer full of spaces
-
- SYNOPSIS
-
- char *spaces (int count)
-
- DESCRIPTION
-
- Returns a pointer to a memory region filled with the specified
- number of spaces and null terminated. The returned pointer is
- valid until at least the next call.
-
- BUGS
-
- */
-
- #include "ansidecl.h"
- #include "libiberty.h"
-
- #if VMS
- #include <stdlib.h>
- #include <unixlib.h>
- #else
- /* For systems with larger pointers than ints, these must be declared. */
- extern PTR malloc PARAMS ((size_t));
- extern void free PARAMS ((PTR));
- #endif
-
- const char *
- spaces (count)
- int count;
- {
- register char *t;
- static char *buf;
- static int maxsize;
-
- if (count > maxsize)
- {
- if (buf)
- {
- free (buf);
- }
- buf = malloc (count + 1);
- if (buf == (char *) 0)
- return 0;
- for (t = buf + count ; t != buf ; )
- {
- *--t = ' ';
- }
- maxsize = count;
- buf[count] = '\0';
- }
- return (const char *) (buf + maxsize - count);
- }
-
-