"MOTION of PROJECTILES in UNIFORM GRAVITY. Without air resistance, a projectiles shot off at an angle THETA with respect to a flat surface has a range RANGE and time of filght TOF that depends on its initial velocity, V0, gravity G and the angle of elevation THETA. * * * shot at * * VELINIT / * * / * * / *___<THETA______________________*_hits surface at time TOF G=gravity: 32 ft/s^2 or 9.8 m/s^2, V0=initial velocity, THETA is the angle of elevation in degrees. (c) Copyright PCSCC, Inc., 1993 *** Answer to problem *** Type ? then (esc) 0 (enter) to set all variables to zero. Set GRAVITY=32 ft/s^2, THETA=40 degrees, set V0=70 ft/s. The RANGE=150.8 ft and TOF=2.82 s. Note only equation TIME is active (followed by equal sign) and TIME is the plot coordinate (followed by colon). Type P, then (esc) 0 to TOF (enter). Type E to exit plot screen. Notice, maximum height = 31.6 ft occurs at about 1.45 s. ||A football is thrown with a perfect spiral at an initial velocity of 70 ft/s an at an angle of 40 degrees with respect to the horizontal.(a) Plot the football's height vs. time. Type comma key to see answers. Type (F2) to return to helpfile."
